Find the average of the prime numbers lying between 50 and 76.
- (a)64
- (b)60
- (c)66
- (d)62
Answer
Why
Correct — A. First list the primes, then take a plain mean.
Primes strictly between 50 and 76: 53, 59, 61, 67, 71, 73 — six numbers.
Every other value in 51–75 carries a factor of 2, 3, 5 or 7.
Add them, showing the running total:
53 + 59 = 112
112 + 61 = 173
173 + 67 = 240
240 + 71 = 311
311 + 73 = 384
Divide by the count: 384 ÷ 6 = 64 → option (a).
Why the others are wrong
- (b)60 — 60 sits below the true mean. The two primes under 60 (53 and 59) fall short of it by only 8 in total, while the four above it (61, 67, 71, 73) exceed it by 32 — a net surplus of 24 over six terms, which lifts the mean to 64.
- (c)66 — 66 demands a total of 66 × 6 = 396. The six primes add to 384, twelve less. Recount the sum before dividing rather than eyeballing the middle of the range.
- (d)62 — 62 is what you get by stopping the list at 71: 53 + 59 + 61 + 67 + 71 = 311, and 311 ÷ 5 = 62.2. 73 is prime too, so the list has six entries, not five.
Concept
A prime has exactly two divisors, 1 and itself. To settle any number below 100 you only need to try 2, 3, 5 and 7 — the next prime is 11, and 11 × 11 = 121 is already past 100.
That trial division is the whole first half of this question. The second half is an ordinary mean: add the values, divide by how many there are.
The examiner's leverage is the list, not the arithmetic. Miss one prime and both the total and the count change, so the mean moves twice.
"Between 50 and 76" is read here as exclusive, but neither 50 nor 76 is prime, so an inclusive reading returns the same six numbers and the same answer.
Key facts
- The primes between 50 and 76 are 53, 59, 61, 67, 71 and 73 — six numbers totalling 384.
- 51 = 3 × 17, 57 = 3 × 19 and 69 = 3 × 23 are composite even though each reads as prime at a glance.
- Testing a number below 100 for primality needs trial division by 2, 3, 5 and 7 only, because 11² = 121 > 100.
Study next
Common traps
- Counting 51, 57 or 69 as prime because they are odd and not obviously factorable.
- Dividing by 5 after having correctly listed six primes.
- Averaging the two endpoints of the range instead of the primes inside it.
The arithmetic is deliberately light so the marks turn on the list. Write the six primes down before adding anything — a recount costs seconds, a wrong list costs the mark.
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