How many squares are present in the following figure?

- (a)19
- (b)21
- (c)17
- (d)23
Answer
Why
Correct — A.
Rule: count by square size, then add.
The figure is a 3 × 3 grid with a small square inside each corner cell and the centre cell.
1 × 1 cells: 9
2 × 2 blocks: 4
Whole frame: 1
Small inner squares: 5
9 + 4 + 1 + 5 = 19 → option (a).
Why the others are wrong
- (b)21 — 21 needs two squares that are not there. Each inner square sits inside its cell without touching a grid line, so it forms nothing larger and counts once.
- (c)17 — 17 is two short. The grid alone gives 9 + 4 + 1 = 14, and the five inner squares, four corners and the centre, bring it to 19.
- (d)23 — 23 overshoots by four. A 2 × 2 block fits in just 4 places in a 3 × 3 grid, and no other lines close into a square.
Concept
Count squares by size, never by eye. Fix the smallest square, then ask how many positions each larger size can take.
In a 3 × 3 grid a 1 × 1 square fits in 9 places, a 2 × 2 in 4 and a 3 × 3 in 1, so the grid alone holds 14. A square drawn inside a cell adds exactly one, because its sides meet no other line.
The response sheet in circulation lost most of this figure's lines.
The figure shown is UnlockIAS's redraw, completed as another published copy of this paper prints it: a 3 × 3 grid with a small square in each corner cell and the centre cell. It counts to 19, SSC's key.
Key facts
- A 3 × 3 grid holds 9 + 4 + 1 = 14 squares.
- An n × n grid holds 1² + 2² + … + n² squares, so a 4 × 4 grid holds 30.
- A square drawn inside a cell, touching none of its sides, adds exactly one.
Study next
Common traps
- Stopping at the nine cells and missing the four 2 × 2 blocks
- Forgetting that the outer frame is itself a square
19 Jan 2026, 11:00 AM, Reasoning Q.29 uses the same 3 × 3 grid with small squares in the top-left and centre cells: 9 + 4 + 1 + 2 = 16, SSC's key there.
Related PYQs
No directly related past PYQ was found.