A sum of Rs. 4800 is divided among A, B, and C in the ratio 3 : 4 : 5. The share of B is how much more than that of A?
- (a)Rs. 500
- (b)Rs. 200
- (c)Rs. 400
- (d)Rs. 300
Answer
Why
Correct — C. Turn the sum into the value of one ratio part.
Total parts: 3 + 4 + 5 = 12
One part: 4800 ÷ 12 = Rs. 400
B − A in parts: 4 − 3 = 1 part
1 part = Rs. 400 → option (c)
Check: A = 3 × 400 = 1200, B = 4 × 400 = 1600, and 1600 − 1200 = 400.
Why the others are wrong
- (a)Rs. 500 — Rs. 500 as one part would make the whole sum 12 × 500 = Rs. 6000, not Rs. 4800. B exceeds A by exactly one part.
- (b)Rs. 200 — Rs. 200 as one part would make the sum 12 × 200 = Rs. 2400, half the given Rs. 4800.
- (d)Rs. 300 — Rs. 300 as one part would make the sum 12 × 300 = Rs. 3600. Rs. 4800 shared into 12 parts gives Rs. 400 a part.
Concept
Dividing a sum in the ratio 3 : 4 : 5 splits it into 12 equal parts: A gets 3, B gets 4 and C gets 5.
Any difference between two shares is a whole number of parts, so find one part first: sum ÷ total parts.
Here B − A = 1 part = Rs. 400, and C − A would be 2 parts = Rs. 800.
The ratio alone fixes B − A as 1⁄12 of the total, so the shares themselves never need to be written out.
Key facts
- Share of one person = (their ratio term ÷ sum of the terms) × total.
- Difference between two shares = (difference of their ratio terms) × value of one part.
- Shares here: A = Rs. 1200, B = Rs. 1600, C = Rs. 2000.
Study next
Common traps
- Dividing by 3, the number of people, instead of 12, the number of parts.
- Giving B's whole share, Rs. 1600, when the question asks how much more B gets than A.
The one-part step runs in reverse at 19 Jan 2026, 11:00 AM, Maths Q.15, where C exceeding B by ₹18,000 fixes the value of a part, and at 15 Sep 2025, 16:00, Quant Q.2 a ₹36,000 bonus is split 4 : 5 : 3 before a second split.
Related PYQs
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