A statement is given followed by two conclusions. Find which conclusion is TRUE based on the given statement. Statement: C < A ≤ T = D ≤ O; G ≤ D < S; T ≥ A Conclusions: I: T ≤ O II: D < T

Correct — C.
Rule: along a chain with every sign facing one way, the result is < if any link is strict, ≤ if none is, and = only if every link is =.

I: T = D and D ≤ O, so T ≤ O. True.
II: the statement gives T = D, so D equals T and cannot be less than it. False.

Only I holds → option (c).

Why the others are wrong

• (a)
  Both I and II — Both I and II accepts D < T, but T = D is stated outright. Two equal letters can never have one strictly smaller than the other.
• (b)
  Neither I nor II — Neither I nor II rejects I, yet T = D ≤ O gives T ≤ O directly. An equals sign passes the ≤ through unchanged.
• (d)
  Only II — Only II reverses the result. II is the false one, since T = D, while I follows from T = D ≤ O.

An inequality item gives a chain of signs and asks which relations are definitely true. Join the two letters of a conclusion through the chain, then combine the signs you pass.

Here T = D ≤ O links T to O through one = and one ≤, which gives T ≤ O. Conclusion II is settled by a single link: T = D rules out D < T.

Key facts

• An = followed by ≤ combines to ≤: T = D ≤ O gives T ≤ O.
• If two letters are joined by =, neither < nor > can hold between them.
• T ≥ A says the same as A ≤ T.

Common traps

• Rejecting T ≤ O because T and O might be equal, though ≤ already allows equality
• Reading the = in T = D as ≤ and treating D < T as possible

No directly related past PYQ was found.