Choose the correct relation: (i) √10 < 3.2 (ii) √11 < √12 (iii) √13 < √14
- (a)(i) only
- (b)(i) and (ii)
- (c)(ii) and (iii)
- (d)(i), (ii) and (iii)
Answer
Why
Correct — D.
For positive numbers, compare squares instead of roots.
(i) Square 3.2: 3.2² = 10.24
10 < 10.24, so √10 < 3.2 → true
(ii) 11 < 12, so √11 < √12 → true
(iii) 13 < 14, so √13 < √14 → true
All three hold → (i), (ii) and (iii) → option (d)
Why the others are wrong
- (a)(i) only — (i) only drops (ii) and (iii), yet both follow at once: the square root keeps order, so 11 < 12 gives √11 < √12 and 13 < 14 gives √13 < √14.
- (b)(i) and (ii) — (i) and (ii) leaves out (iii), which is true for the same reason as (ii): 13 < 14, so √13 < √14.
- (c)(ii) and (iii) — (ii) and (iii) leaves out (i), but 3.2² = 10.24 is more than 10, so √10 ≈ 3.162 really is below 3.2.
Concept
Order survives squaring and square roots for non-negative numbers: if 0 ≤ a < b, then a² < b² and √a < √b.
So (ii) and (iii) need no arithmetic, because the numbers under the roots are already in order.
Relation (i) compares a root with a decimal. Square the decimal instead: 3.2² = 10.24, just above 10, so √10 sits a little under 3.2.
3.2 is a tight bound: √10 ≈ 3.162, about 0.04 below it. Rounding √10 to 3.2 is exactly the slip that makes (i) look false.
Key facts
- For 0 ≤ a < b, √a < √b
- 3.2² = 10.24
- √10 ≈ 3.162
Study next
Common traps
- Rounding √10 to 3.2 and rejecting (i) as 'not less than'
- Picking (ii) and (iii) because they need no arithmetic, without testing (i)
18 Sep 2025, 12:30, Quant Q.3 uses the same squaring move on sums: (√6 + √2)² = 8 + √48 and (√5 + √3)² = 8 + √60, so √6 + √2 is the smaller, and the key marks (i) and (iii) as the incorrect relationships.
Related PYQs
No directly related past PYQ was found.