Read the given statement and conclusions carefully. Decide which of the given conclusions is/are definitely TRUE from the statement. Statement: P > Q < S ≤ T = R ≥ U > V Conclusion I: Q < R Conclusion II: U > T

Correct — A.
Rule: a chain of <, ≤ and = gives < if any sign is strict, ≤ if none is. A sign facing the other way breaks the chain.

I: Q < S ≤ T = R. One strict sign, so Q < R. True.
II: T = R ≥ U gives T ≥ U, that is U ≤ T. U > T contradicts it. False.

Only Conclusion I is True → option (a).

Why the others are wrong

• (b)
  Only Conclusion II is True. — Only II keeps the conclusion the chain rules out. T = R ≥ U puts U at most equal to T, so U > T can never hold.
• (c)
  Both Conclusion I and Conclusion II are True. — Both True needs II, and II reverses the chain: from T = R ≥ U, U cannot be greater than T.
• (d)
  Both Conclusion I and Conclusion II are False. — Both False throws away I. Q < S, S ≤ T and T = R combine to Q < R, since one strict sign is enough.

Read an inequality chain by linking the two letters of a conclusion through every sign between them. Signs facing the same way combine: < with ≤ or = still gives <, and ≥ with = gives ≥.

Where the signs turn round, as in P > Q < S, the ends cannot be compared at all. P and V play no part here. Conclusion I needs the stretch from Q to R, and II the stretch from T to U.

Key facts

• A chain of <, ≤ and = in one direction gives < if any sign in it is strict.
• T = R ≥ U gives T ≥ U, which is the same as U ≤ T.
• Letters joined through signs that face opposite ways, as in P > Q < S, cannot be compared.

Common traps

• Reading T = R ≥ U backwards and accepting U > T
• Treating ≤ as a break in the chain and rejecting Q < R

No directly related past PYQ was found.