Reena borrowed Rs. 1200 at simple interest for a number of years equal to the rate of interest. At the end of the loan term, she paid Rs. 432 in interest. What was the interest rate?
- (a)6%
- (b)7%
- (c)8%
- (d)9%
Answer
Why
Correct — A. Use SI = P × R × T ⁄ 100 with T = R.
Substitute: 432 = 1200 × R × R ⁄ 100
Simplify: 432 = 12R²
Divide by 12: R² = 36
Take the square root: R = 6
So the rate is 6% a year, for 6 years → option (a).
Why the others are wrong
- (b)7% — 7% for 7 years gives 1200 × 7 × 7 ⁄ 100 = Rs. 588 of interest, not Rs. 432.
- (c)8% — 8% for 8 years gives 12 × 64 = Rs. 768 of interest, far above the Rs. 432 she paid.
- (d)9% — 9% for 9 years gives 12 × 81 = Rs. 972, more than double the Rs. 432 of interest.
Concept
Simple interest is P × R × T ⁄ 100. When the stem ties the time to the rate, the two unknowns become one: here T = R, so the formula becomes 1200 × R² ⁄ 100 = 12R².
That makes it a perfect-square question: 432 ÷ 12 = 36 = 6². With whole-number options, R² has to come out as a perfect square, so a messy quotient means an arithmetic slip.
The 36 that appears on the way is R × T, the total interest as a percentage of the principal (432 ⁄ 1200 = 36%). The rate is its square root, not 36% itself.
Key facts
- Simple interest = P × R × T ⁄ 100, with R in % per annum and T in years.
- When T = R, SI = P × R² ⁄ 100.
- Rs. 1200 at 6% for 6 years earns 1200 × 36 ⁄ 100 = Rs. 432.
Study next
Common traps
- Solving 432 = 12R as if the time were 1 year, which gives R = 36.
- Reading 432 ⁄ 1200 = 0.36 as a 36% rate, when 36 is the rate multiplied by the time.
10 Sep 2024, 16:00, Quant Q.7 ties rate to time the same way: the rate is 5 times the years and the interest is one-fifth of the sum, so 5T² = 20, T = 2 and R = 10%.
It then raises the rate by 3%, read as 10% + 3% = 13%, and asks for the interest on ₹5,600 for 6 years: 5600 × 13 × 6 ⁄ 100 = 4368, the keyed answer.
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