Evaluate: (0.04³ + 0.02³) ÷ (0.2³ + 0.1³)
- (a)0.008
- (b)0.004
- (c)0.002
- (d)0.016
Answer
Why
Correct — A. Each number on top is 0.2 times the matching number below, so pull 0.2³ out instead of expanding.
Rewrite: 0.04 = 0.2 × 0.2 and 0.02 = 0.2 × 0.1
Factor the cubes: 0.04³ + 0.02³ = 0.2³ × (0.2³ + 0.1³)
Cancel the common bracket: quotient = 0.2³
Cube: 0.2 × 0.2 × 0.2 = 0.008
Check with direct values: 0.000064 + 0.000008 = 0.000072, and 0.008 + 0.001 = 0.009
Divide: 0.000072 ÷ 0.009 = 0.008 → option (a)
Why the others are wrong
- (b)0.004 — 0.004 is half the quotient: 0.004 × 0.009 = 0.000036, only half of the numerator 0.000072.
- (c)0.002 — 0.002 is a quarter of the quotient: 0.002 × 0.009 = 0.000018, one quarter of the numerator 0.000072.
- (d)0.016 — 0.016 is double the quotient: 0.016 × 0.009 = 0.000144, twice the numerator 0.000072.
Concept
When every term inside a sum of cubes is multiplied by the same factor k, the sum is multiplied by k³: (ka)³ + (kb)³ = k³(a³ + b³).
Here 0.04 and 0.02 are 0.2 × 0.2 and 0.2 × 0.1, so the numerator is exactly 0.2³ times the denominator and the quotient is 0.2³ = 0.008. Spotting the factor avoids six-decimal-place arithmetic, where one miscounted zero wrecks the answer.
Key facts
- (ka)³ + (kb)³ = k³(a³ + b³).
- 0.2³ = 0.008 and 0.1³ = 0.001.
- Cubing a decimal triples its decimal places: 0.04 has two, so 0.04³ = 0.000064 has six.
Study next
Common traps
- Miscounting decimal places in the cubes: 0.04³ is 0.000064, with six places, not 0.00064.
- Taking the common factor as 0.2 instead of 0.2³: the factor comes out of each cube, so it is cubed too.
19 Sep 2025, 09:00, Quant Q.25 is another quotient of decimal cubes: 0.5 + 0.1 − 0.6 = 0, so 0.5³ + 0.1³ − 0.6³ = 3 × 0.5 × 0.1 × (−0.6), and the quotient is −1.
18 Sep 2024, 12:30, Quant Q.2 cancels [(7.3)³ − (4.7)³] against (7.3)² + 7.3 × 4.7 + (4.7)² to leave 7.3 − 4.7 = 2.6.
Related PYQs
No directly related past PYQ was found.