Find the value of √(388 + √(127 + √289))

- (a)20
- (b)30
- (c)40
- (d)50
Answer
Why
Correct — A. Clear the roots from the inside out.
Innermost root: √289 = 17
Add: 127 + 17 = 144
Middle root: √144 = 12
Add: 388 + 12 = 400
Outer root: √400 = 20 → option (a).
Why the others are wrong
- (b)30 — 30² = 900, so 30 would need 900 under the outer root. The working puts 388 + 12 = 400 there, and √400 = 20.
- (c)40 — 40² = 1600, four times the 400 that actually sits under the outer root. Squaring each option and comparing with 400 rules 40 out in one step.
- (d)50 — 50² = 2500, over six times the 400 under the outer root. 388 plus the small middle root (12) cannot come anywhere near 2500.
Concept
A nested root built like this collapses layer by layer: each inner result, added to the next number, makes a perfect square.
Here 127 + 17 = 144 = 12² and 388 + 12 = 400 = 20². Knowing the squares up to 30² lets you see each step at once.
A check from the options: square each option. Only 20² = 400 sits just above 388.
Treat the root signs like nested brackets. The outer root cannot be taken until everything under it, including the inner roots, has been reduced to one number.
Key facts
- √289 = 17, √144 = 12 and √400 = 20.
- Nested roots are evaluated from the innermost root outward, like nested brackets.
- √(a + b) is not √a + √b: √(388 + 12) = 20, while √388 + √12 ≈ 19.70 + 3.46 = 23.16.
Study next
Common traps
- Splitting a root across a sum, as if √(388 + 12) were √388 + √12.
- Starting at the outer root and trying to take √388 before the inner roots are cleared.
An infinite nested root is asked 17 Sep 2025, 16:00, Quant Q.3: √(12 + √(12 + …)) is keyed 4, found by solving x² = 12 + x rather than peeling layers.
19 Sep 2025, 09:00, Quant Q.1 asks the denesting form √(9 + 4√5), keyed √5 + 2.
Related PYQs
No directly related past PYQ was found.