In a trapezoid, the two parallel sides are in the ratio 3:5. If the height of the trapezoid is 10 cm and its total area is 240 cm², determine the lengths of the parallel sides.
- (a)15 cm and 25 cm
- (b)18 cm and 30 cm
- (c)20 cm and 40 cm
- (d)30 cm and 50 cm
Answer
Why
Correct — B. Turn the ratio into lengths with one unknown, then use the trapezium area formula.
Sides in the ratio 3:5: 3k and 5k
Area = ½ × (sum of parallel sides) × height
Substitute: 240 = ½ × (3k + 5k) × 10
Simplify the right side: ½ × 8k × 10 = 40k
Solve 40k = 240: k = 6
Sides: 3 × 6 = 18 cm and 5 × 6 = 30 cm
Check the area: ½ × (18 + 30) × 10 = 240 cm² → option (b)
Why the others are wrong
- (a)15 cm and 25 cm — 15 and 25 keep the 3:5 ratio but give the wrong area: ½ × (15 + 25) × 10 = 200 cm², not 240 cm².
- (c)20 cm and 40 cm — 20 : 40 is 1 : 2, not 3 : 5, so it fails the ratio before the area is checked. Its area would also be wrong: ½ × 60 × 10 = 300 cm².
- (d)30 cm and 50 cm — 30 and 50 are in the ratio 3:5 but give too much area: ½ × (30 + 50) × 10 = 400 cm². That is k = 10, not k = 6.
Concept
A trapezium's area is ½ × (sum of the parallel sides) × height: the average of the two parallel sides times the distance between them.
When the sides are given only as a ratio, turn it into lengths with one multiplier, so 3:5 becomes 3k and 5k. The area equation then has a single unknown, and each option can be tested twice: once for the ratio, once for the area.
The paper says trapezoid, the American name. NCERT textbooks call the same figure, a quadrilateral with one pair of parallel sides, a trapezium.
Key facts
- Area of a trapezium = ½ × (a + b) × h, where a and b are the parallel sides and h is the perpendicular distance between them.
- A ratio p : q of unknown size is written as pk and qk before it goes into a formula.
- Here k = 6: the sides 18 cm and 30 cm average 24 cm, and 24 × 10 = 240 cm².
Study next
Common traps
- Picking 15 cm and 25 cm because the 3:5 ratio fits, without checking the area.
- Dropping the ½: (3k + 5k) × 10 = 240 gives k = 3 and sides of 9 cm and 15 cm.
The ratio-to-k step also opens 21 Sep 2025, 16:00, Quant Q.11: legs in the ratio 5:12 with a 13 m hypotenuse give 5k, 12k and 13k with k = 1, so the area is ½ × 5 × 12 = 30 m².
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