Find the option that best completes the analogy. DP : XZ :: EN : ?
- (a)YZ
- (b)YB
- (c)ZB
- (d)YX
Answer
Why
Correct — D.
Rule: first letter +20, second letter +10.
D(4) + 20 = X(24)
P(16) + 10 = Z(26)
E(5) + 20 = Y(25)
N(14) + 10 = X(24)
So EN becomes YX → option (d).
Why the others are wrong
- (a)YZ — YZ gets the first letter right, but Z is N + 12. In DP → XZ the second letter moves +10, and N(14) + 10 is X.
- (b)YB — YB puts B second, which is N + 14 after wrapping past Z. The given pair moves the second letter +10, landing N on X.
- (c)ZB — ZB moves E by +21 and N by +14. Both overshoot: DP → XZ fixes the shifts at +20 and +10, which give Y and X.
Concept
Turn each letter into its alphabet position (A = 1 … Z = 26) and measure how far each one moves from the first pair to the second.
Work one position at a time. Here the first letter moves +20 and the second +10, so the two shifts differ. Apply each shift to the letter in the same position of the second pair: E takes +20, N takes +10.
Counting backwards gives the same letters: first letter −6 (D → X and E → Y, wrapping past A), second letter −16 (P → Z and N → X). Either direction lands on YX.
Key facts
- D = 4, E = 5, N = 14, P = 16, X = 24, Y = 25, Z = 26.
- On a 26-letter wheel, a shift of +20 is the same as −6.
- Each letter of a pair can move by its own amount, so measure both.
Study next
Common traps
- Applying the first letter's +20 to both letters: N + 20 wraps to H, which is in no option
- Checking the first letter alone: YZ, YB and YX all start with Y, so the second letter decides
12 Sep 2025, 09:00, Reasoning Q.12 uses the same frame, AG : IO :: CM : ?, with both letters moving +8 (keyed KU).
17 Sep 2025, 16:00, Reasoning Q.13 does the same with AB : IJ :: EF : ?, keyed MN.
Related PYQs
No directly related past PYQ was found.