The given statements are followed by two conclusions. Find out which conclusion is TRUE based on the given statements. Statements: S > T = U, V ≥ W < T, O = S = P, W > Q > R Conclusions: I. T= O II. T > O
- (a)Only conclusion I is true
- (b)Only conclusion II is true
- (c)Both conclusion I and II are true
- (d)Neither conclusion I nor II is true
Answer
Why
Correct — D.
Rule: join T and O through a shared letter, then read the combined sign.
O = S (from O = S = P)
S > T (from S > T = U)
So O > T, which means T < O.
I says T = O and II says T > O. The chain rules out both → option (d).
Why the others are wrong
- (a)Only conclusion I is true — T = O would need equals signs all the way along. The chain has S > T in it, so O is strictly greater than T.
- (b)Only conclusion II is true — T > O points the wrong way. O equals S, and S is greater than T, so T is smaller than O.
- (c)Both conclusion I and II are true — Both cannot hold even in principle, since T cannot equal O and exceed it at once. Here the chain gives T < O, so each fails.
Concept
In inequality items, connect the two letters in a conclusion through the statements and keep the strongest sign met on the way. One strict sign (> or <) in a chain that points one way makes the result strict.
Here the path from O to T is O = S > T. The statements about U, V, W, Q and R are not needed for this pair.
Conclusions I and II together cover T ≥ O, the exact opposite of what the chain proves. With the relation fixed as T < O, neither can be true.
Key facts
- In a chain whose signs all point one way, a single strict sign makes the result strict: O = S > T gives O > T.
- Signs pointing opposite ways, as in V ≥ W < T, give no relation between V and T.
- T = O and T > O together make T ≥ O, the opposite of T < O.
Study next
Common traps
- Reading S > T = U and O = S = P separately and missing that S joins them
- Reading the chain from the wrong end and choosing T > O
21 Sep 2025, 16:00, Reasoning Q.7 tests the equals sign from the other side: with T = D, the conclusion D < T fails while T ≤ O holds (keyed Only I).
19 Sep 2025, 09:00, Reasoning Q.7 runs Q < S ≤ T = R, so Q < R is true and U > T is not (keyed Only Conclusion I is True).
Related PYQs
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