A gardener organizes plants into rows to create a square formation but discovers that 15 plants are not included. If the total number of plants is 3984, then what is the number of plants in each row?
- (a)43
- (b)45
- (c)63
- (d)65
Answer
Why
Correct — C. The plants that fit form a perfect square: as many rows as plants in each row.
Plants in the square: 3984 − 15 = 3969
Bracket it: 60² = 3600 and 70² = 4900, so the root lies in the 60s
Last digit 9: the root ends in 3 or 7, so try 63
Square it: (60 + 3)² = 3600 + 360 + 9 = 3969
Plants in each row: 63 → option (c)
Why the others are wrong
- (a)43 — 43² = 1849, and 1849 + 15 = 1864 plants, less than half the 3984 the gardener has.
- (b)45 — 45² = 2025, so this square plus the 15 left over is only 2040 plants, not 3984.
- (d)65 — 65² = 4225, more than the 3984 plants in total. A square that size cannot be formed at all, let alone with 15 to spare.
Concept
A square formation has as many rows as plants in each row, so a formation of n rows uses n² plants. Whatever does not fit is left over: total = n² + leftover.
So take the leftover away first, then find the square root. Prime factors confirm it: 3969 = 3⁴ × 7², so √3969 = 3² × 7 = 63.
The answer is also the largest square the plants allow. The next square, 64² = 4096, is more than 3984, and the 15 left over is far below the 2 × 63 + 1 = 127 extra plants a 64-row square would need.
Key facts
- A square formation of n rows holds n² items, so total = n² + leftover.
- 3969 = 3⁴ × 7², so √3969 = 63.
- A perfect square never ends in 2, 3, 7 or 8.
- A perfect square ending in 9 has a square root ending in 3 or 7.
Study next
Common traps
- Adding the 15 instead of subtracting it: 3984 + 15 = 3999 is not a perfect square, since 63² = 3969 and 64² = 4096.
- Taking √3984 ≈ 63.1 as a sign something is wrong. The 15 plants left over are exactly why 3984 is not a perfect square.
The square is hidden in a word problem: total minus leftover is n².
Knowing squares up to 70 also settles 18 Sep 2025, 12:30, Quant Q.2 from the inside out: √289 = 17, √(127 + 17) = √144 = 12, and √(388 + 12) = √400 = 20.
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