Given: P & Q: P is the husband of Q P % Q: P is the daughter of Q P # Q: P is the father of Q P @ Q: P is the brother of Q What does R # S & T mean?
- (a)R is the father of T
- (b)R is the brother of T
- (c)R is the father-in-law of T
- (d)R is the husband of T
Answer
Why
Correct — C.
Rule: decode one symbol at a time, left to right.
R # S → R is the father of S.
S & T → S is the husband of T.
So T is the wife of R's son S, and R is T's father-in-law → option (c).
Why the others are wrong
- (a)R is the father of T — Father of T stops at the first link. R is the father of S, and T is S's wife, so T joins R's family by marriage, not birth.
- (b)R is the brother of T — Brother needs the @ symbol, and the expression has none. R is the father of T's husband, a generation above her.
- (d)R is the husband of T — Husband of T is S, not R. The & sign links S to T, and R is linked only to S.
Concept
In a coded relation, each symbol joins the two letters on either side of it. R # S & T is two statements, R # S and S & T, sharing S.
Chain them through S: R's son is married to T. T is R's daughter-in-law, so R is her father-in-law.
The & code fixes S as male, because S is a husband. That is what makes S the son of R rather than a daughter. The % and @ codes are not used here.
Key facts
- R # S: R is the father of S.
- S & T: S is the husband of T, so S is male.
- The father of a woman's husband is her father-in-law.
Study next
Common traps
- Reading R # S & T as R # T and choosing father of T
- Missing that & makes S male, which is what turns S into R's son
19 Sep 2024, 09:00, Reasoning Q.2 runs the same parent-then-spouse chain with other symbols: A × B ÷ C × D makes A the mother of C and C the wife of D, and A is keyed as D's wife's mother.
Related PYQs
No directly related past PYQ was found.