After interchanging + & × and 15 & 30, which of the following equations will hold true?
- (a)(15+2)×30=60
- (b)(30+3)×15=40
- (c)(15+4)×30=135
- (d)(30+1)×15=40
Answer
Why
Correct — C. Make both swaps in each option, then work it out.
Rule: + ↔ × and 15 ↔ 30, with the brackets left where they are.
Printed: (15 + 4) × 30 = 135
After the swaps: (30 × 4) + 15
Bracket first: 30 × 4 = 120
Add: 120 + 15 = 135, which matches
So the equation that holds is option (c).
Why the others are wrong
- (a)(15+2)×30=60 — (15+2)×30=60 becomes (30 × 2) + 15 = 60 + 15 = 75, not 60.
- (b)(30+3)×15=40 — (30+3)×15=40 becomes (15 × 3) + 30 = 45 + 30 = 75, not 40.
- (d)(30+1)×15=40 — (30+1)×15=40 becomes (15 × 1) + 30 = 15 + 30 = 45, not 40.
Concept
An interchange item asks you to rewrite each option before judging it. Two swaps happen together here: the signs + and ×, and the numbers 15 and 30.
Make both swaps in a single pass, so a 15 that has just become 30 is not turned back into 15. Brackets are not operators: they stay where they are, so (30 × 4) + 15 is worked bracket first.
Both swaps are needed. Swapping the numbers alone turns option (c) into (30 + 4) × 15 = 510, and swapping the signs alone gives (15 × 4) + 30 = 90. Neither is 135.
Key facts
- After the swaps, (15 + 4) × 30 reads (30 × 4) + 15 = 135.
- Brackets keep their place when signs and numbers are interchanged.
- Both swaps apply at once: 15 becomes 30 and 30 becomes 15 in the same pass.
Study next
Common traps
- Swapping in two passes, 15 → 30 and then every 30 → 15, which turns the new 30s straight back into 15s.
- Making one swap and forgetting the other, which gives 510 or 90 for option (c) instead of 135.
The same double swap is set at 12 Sep 2025, 16:00, Reasoning Q.22, with + ↔ × and 3 ↔ 9, where (3+5)×9=48 becomes (9 × 5) + 3 = 48.
Related PYQs
No directly related past PYQ was found.