A certain amount grows to ₹6400 in 2 years and ₹7040 in 3 years. Determine the interest rate.
- (a)10%
- (b)9%
- (c)8%
- (d)11%
Answer
Why
Correct — A.
Growth from year 2 to year 3 = 7040 − 6400 = ₹640
With compound interest, that year's interest is earned on the year-2 amount, ₹6400.
Rate = 640 ÷ 6400 × 100 = 10%
Check: 6400 × 1.10 = 7040 → option (a).
Why the others are wrong
- (b)9% — 9% grows ₹6400 to ₹6976, not ₹7040. 9% is roughly 640 ÷ 7040, which puts the later amount in the denominator instead of the amount the interest was earned on.
- (c)8% — 8% grows ₹6400 to ₹6912 in the third year, ₹128 short of ₹7040. The year's gain of ₹640 is 10% of ₹6400.
- (d)11% — 11% overshoots: 6400 × 1.11 = ₹7104, which is ₹64 more than the ₹7040 the stem gives.
Concept
Under compound interest, each year's interest is earned on the amount at the start of that year. So the growth between two consecutive years, divided by the earlier amount, is the rate.
Here the growth from year 2 to year 3 is ₹640 on ₹6400, which is 10%. The principal is never needed.
Under simple interest the ₹640 would be added every year, putting the principal at ₹5120 and the rate at 12.5%.
The stem, as printed, does not say simple or compound interest. Read as simple interest, the same two amounts give 12.5%, which no option offers. The keyed 10% is the compound-interest reading.
Key facts
- Compound interest: amount after n years = P(1 + r⁄100)ⁿ.
- For consecutive years, rate = (next amount − earlier amount) ÷ earlier amount × 100.
- Simple-interest amounts rise by the same rupee sum each year, not by the same percentage.
Study next
Common traps
- Dividing ₹640 by ₹7040 instead of ₹6400, which gives about 9.1%.
- Working it as simple interest and hunting for 12.5%.
15 Sep 2025, 16:00, Quant Q.10 asks the same with ₹12,000 and ₹13,200 at the end of years 2 and 3, and names compound interest: ₹1,200 on ₹12,000 is again 10%.
12 Sep 2025, 09:00, Quant Q.11 gives ₹6,600 and ₹7,920 at compound interest and asks for the principal instead.
Related PYQs
No directly related past PYQ was found.