Find the group of letters that best completes the analogy. Use alphabetical positions and reverse position logic where necessary. DINS : WRMH :: EKPT : ?

Correct — C.
Rule: each letter becomes its opposite, the letter whose position adds with it to 27.

D(4) → W(23), I(9) → R(18), N(14) → M(13), S(19) → H(8).
Every pair sums to 27, and the order is kept.

E(5) → V(22), K(11) → P(16), P(16) → K(11), T(20) → G(7).
That gives VPKG → option (c).

Why the others are wrong

• (a)
  VJOG — VJOG gets V and G right but not the middle. K's opposite is P (11 + 16 = 27), not J, and P's opposite is K, not O.
• (b)
  VJNF — VJNF gets V right and nothing else. K pairs with P, P pairs with K, and T pairs with G (20 + 7 = 27), not F.
• (d)
  VJOF — VJOF has V right, then J, O and F, none of which adds to 27 with K, P or T. Those opposites are P, K and G.

Opposite letters are the pairs that meet from both ends of the alphabet: A and Z, B and Y, C and X. Their positions always add to 27, so the opposite of the letter at position n sits at 27 − n.

The stem's hint, 'reverse position logic', points here. EKPT holds K and P, which are each other's opposites, so in the answer they swap places.

Key facts

• Opposite letters add to 27: E(5) and V(22), K(11) and P(16), T(20) and G(7).
• The opposite of the letter at position n is at 27 − n.
• M(13) and N(14) are opposites, the middle pair of the alphabet.

Common traps

• Using 26 − n instead of 27 − n, which puts every letter one place off
• Reversing the order of the letters as well, which the DINS pair does not do

No directly related past PYQ was found.