If 5 @ 3 = 28 and 4 @ 2 = 18, then what is 6 @ 4?
- (a)40
- (b)52
- (c)64
- (d)76
Answer
Why
Correct — A. Rule: a @ b = a² + b (square the first number, add the second).
5 @ 3 = 25 + 3 = 28 ✓
4 @ 2 = 16 + 2 = 18 ✓
6 @ 4 = 6² + 4
= 36 + 4 = 40 → option (a)
Why the others are wrong
- (b)52 — 52 is 6² + 4², squaring both numbers. That rule gives 5² + 3² = 34 for the first example, not the printed 28.
- (c)64 — 64 would need 28 added to 6² = 36. The examples add only the second number, 3 and then 2, so 6 @ 4 adds 4.
- (d)76 — 76 would need 40 added to 6² = 36, ten times the second number. The examples add the second number itself: 25 + 3 and 16 + 2.
Concept
With a made-up operator, look for a square when each result sits just above one. 28 is 3 more than 25 = 5², and 18 is 2 more than 16 = 4².
The amount over the square is the second number each time. That gives a² + b, which you check against both examples before applying it to 6 @ 4.
Test every rule on both examples. a × b + 13 fits 5 @ 3 = 28 but gives 21 for 4 @ 2, so it is not the rule, while a² + b fits both.
Key facts
- 5² + 3 = 28 and 4² + 2 = 18.
- 6² + 4 = 40.
- Squares worth knowing on sight: 16, 25, 36, 49, 64, 81.
Study next
Common traps
- Squaring both numbers, which gives 6² + 4² = 52.
- Trusting a rule after one example: a × b + 13 fits 5 @ 3 but not 4 @ 2.
An operator rule also decides 14 Sep 2025, 12:30, Reasoning Q.15, where 9 @ 3 = 36 and 6 @ 2 = 16 fit (a + b) × b, and 19 Sep 2025, 09:00, Reasoning Q.20, where 9 % 2 = 81 squares the first number.
Related PYQs
No directly related past PYQ was found.