If x+2y=14 and x−y=5, find x.
- (a)6
- (b)4
- (c)8
- (d)10
Answer
Why
Correct — C. Rule: subtract one equation from the other so that x cancels.
(x + 2y) − (x − y) = 14 − 5
3y = 9
y = 9 ÷ 3 = 3
Put y = 3 into x − y = 5:
x = 5 + 3 = 8 → option (c)
Check in the other equation: 8 + 2 × 3 = 14 ✓
Why the others are wrong
- (a)6 — x = 6 forces y = 1 from x − y = 5, and then x + 2y = 6 + 2 = 8, not 14.
- (b)4 — x = 4 forces y = −1 from x − y = 5, and then x + 2y = 4 − 2 = 2, not 14.
- (d)10 — x = 10 forces y = 5 from x − y = 5, and then x + 2y = 10 + 10 = 20, not 14.
Concept
These two equations have exactly one solution, because their x : y coefficient ratios differ: 1 : 2 against 1 : −1.
Elimination removes one letter by adding or subtracting the equations. Here both carry a single x, so subtracting them cancels x at once and leaves 3y = 9.
With y known, either equation gives x. Putting both values back into the other equation is the check that catches a sign slip.
Testing the options is just as fast here: each x gives y from x − y = 5, and x = 8 is the value that also satisfies x + 2y = 14.
Key facts
- Subtracting x − y = 5 from x + 2y = 14 gives 3y = 9.
- The solution is x = 8, y = 3.
- A pair solves the system only if it satisfies both equations.
Study next
Common traps
- Adding the equations instead of subtracting, which gives 2x + y = 19 and removes neither letter.
- Subtracting y's terms with the wrong sign: 2y − (−y) is 3y, not y.
Removing one unknown at a time also decides 11 Sep 2024, 09:00, Quant Q.16, where x + 2z = 3 and 3x − 5z = −13 give z = 2 and x = −1 before y is found.
Related PYQs
No directly related past PYQ was found.