In each of the following questions, a group of three numbers/symbols is given in each option. Identify the group that does NOT follow the same pattern as the others.
- (a)Z1# : Y2@ : X3$
- (b)W4% : V5^ : U6&
- (c)T7* : S8( : R9)
- (d)Q10_ : P9@ : O8$
Answer
Why
Correct — D.
Rule: letters fall by one while numbers rise by one.
(a) Z, Y, X with 1, 2, 3.
(b) W, V, U with 4, 5, 6.
(c) T, S, R with 7, 8, 9.
Q10_ : P9@ : O8$ keeps the falling letters, but its numbers run 10, 9, 8, downwards → option (d).
Why the others are wrong
- (a)Z1# : Y2@ : X3$ — Z, Y, X fall by one while 1, 2, 3 rise by one, the shared pattern. The group fits.
- (b)W4% : V5^ : U6& — W, V, U fall by one and 4, 5, 6 rise by one, exactly as in (a) and (c). The group fits.
- (c)T7* : S8( : R9) — T, S, R fall by one and 7, 8, 9 rise by one. Its symbols, an asterisk and two brackets, look different but do not decide anything.
Concept
Each term here has three strands: a letter, a number and a symbol. Test each strand on its own and keep the one that splits the options three to one.
Letters: every group falls by one, so they cannot decide. Symbols: every group carries three different ones, so they cannot decide either. Numbers: (a), (b) and (c) rise by one, and (d) falls.
Read across the options and the letters run Z to O without a break, while the numbers run 1 to 9 and then 10. Option (d) starts where the count should continue, then turns back.
Key facts
- The letters of the four groups form one descending chain, Z down to O.
- Numbers rise 1 to 3, 4 to 6 and 7 to 9 in (a), (b) and (c), and fall 10, 9, 8 in (d).
- Every group carries three different symbols.
Study next
Common traps
- Stopping at the letters, which fall by one in all four groups
- Accepting Q10 because 10 continues the count from 9, without checking the next two numbers
12 Sep 2025, 09:00, Reasoning Q.21 prints the same instruction with the same kind of symbols, but there each number is its letter's position (A1, B2, C3) and a repeated @ in option (d) decides.
Related PYQs
No directly related past PYQ was found.