Simplify: [25 − 48 ÷ 6 + 12 × 2] + 78 − [5 + 3 of (25 − 2 × 10)]
- (a)89
- (b)90
- (c)98
- (d)99
Answer
Why
Correct — D. Reduce each bracket to a single number first, then read what is left from left to right.
First bracket: 48 ÷ 6 = 8 and 12 × 2 = 24
25 − 8 + 24 = 41
Second bracket: 25 − 2 × 10 = 25 − 20 = 5
3 of 5 = 15, so 5 + 15 = 20
41 + 78 − 20 = 99 → option (d)
Why the others are wrong
- (a)89 — 89 needs the second bracket to come to 30. Inside it the multiplication goes first, so 25 − 2 × 10 = 5 and 5 + 3 of 5 = 20, leaving no way to reach 30.
- (b)90 — 90 needs the second bracket to be 29. The inner bracket is 5 and 3 of 5 is 15, so the only value available is 5 + 15 = 20.
- (c)98 — 98 needs the first bracket to be 40. But 48 ÷ 6 = 8 and 12 × 2 = 24, so 25 − 8 + 24 = 41 exactly, with no slack anywhere.
Concept
BODMAS is the whole question, and the word of is what decides it.
'Of' is a multiplication that ranks above division, so 3 of 5 = 15 and would be settled first if a division stood beside it. Nothing divides it here, so it behaves as an ordinary product.
Inside every bracket the same order applies: multiply and divide before adding and subtracting. That turns 25 − 2 × 10 into 25 − 20, not 23 × 10.
Addition and subtraction rank equally, so 25 − 8 + 24 is read left to right: 17, then 41. Doing 8 + 24 first would give 25 − 32 = −7.
Key facts
- In BODMAS 'of' is a multiplication resolved ahead of division.
- 25 − 48 ÷ 6 + 12 × 2 = 25 − 8 + 24 = 41.
- 5 + 3 of (25 − 2 × 10) = 5 + 3 of 5 = 5 + 15 = 20.
- 41 + 78 − 20 = 99.
Study next
Common traps
- Adding 8 + 24 before subtracting from 25, which turns the first bracket into −7
- Reading 25 − 2 × 10 as (25 − 2) × 10 = 230
- Treating 'of' as an ordinary multiplication when a division sits beside it
SSC builds these so that one bracket punishes a precedence slip. The 'of' form is asked at 13 Sep 2024, 09:00, Quant Q.15 and at 26 Sep 2024, 12:30, Quant Q.19. A decimals-and-braces version runs at 10 Sep 2024, 12:30, Quant Q.25.
Related PYQs
No directly related past PYQ was found.