The value of (x + y)² + (x − y)² is equal to:

- (a)

- (b)

- (c)

- (d)

Answer
Why
Correct — D. The stem and all four options are images. The stem asks for the value of (x + y)² + (x − y)², and option (d) shows 2(x² + y²).
(x + y)² = x² + 2xy + y²
(x − y)² = x² − 2xy + y²
Add the two: the +2xy and −2xy cancel
Sum = 2x² + 2y² = 2(x² + y²) → option (d)
Why the others are wrong
- (a)Option (a) shows 4xy, which is (x + y)² − (x − y)². Subtracting keeps the cross term and cancels the squares — the exact opposite of what adding does.
- (b)Option (b) shows (2x + 2y)² = 4x² + 8xy + 4y². The surviving 8xy settles it: the true sum has no xy term at all.
- (c)Option (c) shows 2(x + y)² = 2x² + 4xy + 2y². That treats (x − y)² as equal to (x + y)², which is only true when xy = 0.
Concept
Two identities do all the work here, and they are worth holding as a pair.
(a + b)² + (a − b)² = 2(a² + b²)
(a + b)² − (a − b)² = 4ab
Adding cancels the cross term; subtracting cancels the squares. Every option printed here is one of those two results or a mis-square of them, so recognising the pair settles the item without expanding anything.
Substituting x = 2 and y = 1 separates all four options in seconds: they come to 8, 36, 18 and 10, while the expression itself is 3² + 1² = 10.
Key facts
- (a + b)² + (a − b)² = 2(a² + b²), because the 2ab terms cancel.
- (a + b)² − (a − b)² = 4ab, because the squares cancel instead.
- At x = 2 and y = 1 the expression is 3² + 1² = 10, matching 2(4 + 1).
Study next
Common traps
- Answering 4xy, which is the difference of the two squares rather than their sum
- Adding what is inside the brackets first and then squaring
- Confusing the option images 2(x + y)² and 2(x² + y²), where the squares sit in different places
Both the stem and every option arrive as pictures, so the item turns on reading where each square sits before any algebra begins.
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