Select the combination of letters that when sequentially placed in the blanks of the given series will complete the series. _TUVTR_WU_UXVN_Y

Correct — B. The string is 16 letters long, so cut it into groups of four and stack them: _TUV / TR_W / U_UX / VN_Y.

Rule: column 1 rises +1 (S, T, U, V), column 2 falls −2 (T, R, P, N), column 3 stays U throughout, column 4 rises +1 (V, W, X, Y).

The four gaps are column 1 of group 1, column 3 of group 2, column 2 of group 3 and column 3 of group 4.
They therefore take S, U, P, U, which is option (b).

Why the others are wrong

• (a)
  SUUP — SUUP puts U into the second column of group 3, but that column runs T, R, ?, N — a steady −2 that needs P. Its last two letters are the right ones in the wrong order.
• (c)
  PSVU — PSVU opens with P, so the first column would read P, T, U, V instead of the +1 chain S, T, U, V.
• (d)
  SVUP — SVUP drops V into the third column, which is fixed at U in every group — the one column that never moves.

A blank-filling letter series is a table in disguise. Count the letters, find a group length that divides the count — 16 here, so groups of four — and write the groups one under another.

Each column then becomes its own short series, and every gap sits in exactly one column. One hard sixteen-letter problem turns into four easy four-letter ones.

A column that never changes is as much a rule as one that climbs, and it is the cheapest one to check.

Key facts

• The series holds 16 letters, which is why groups of four expose the pattern.
• Column 2 falls T, R, P, N, a constant −2 step.
• Column 3 reads U in all four groups.

Common traps

• Reading the string as one long series instead of stacking it into groups.
• Filling the gaps in group order rather than in the order they appear in the string.
• Missing that one column can stay constant.

No directly related past PYQ was found.