Select the set in which the numbers are related in the same way as are the numbers of the following set. (84, 63, 42) (79, 47, 64) (NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into its constituent digits. E.g. 13 – Operations on 13 such as adding/deleting/multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed.)
- (a)(71, 53, 36)
- (b)(64, 51, 52)
- (c)(67, 48, 57)
- (d)(75, 33, 48)
Answer
Why
Correct — A. The third number is fixed by the gap between the first two.
Rule: third = 2 × (first − second).
(84, 63, 42): 84 − 63 = 21, and 2 × 21 = 42
(79, 47, 64): 79 − 47 = 32, and 2 × 32 = 64
Testing option (a): 71 − 53 = 18, and 2 × 18 = 36
So (71, 53, 36) obeys the same relation.
Why the others are wrong
- (b)(64, 51, 52) — 64 − 51 = 13, so the third number should be 26. The printed 52 is 4 × 13, twice too large.
- (c)(67, 48, 57) — 67 − 48 = 19, so the third number should be 38. The printed 57 is 3 × 19.
- (d)(75, 33, 48) — 75 − 33 = 42, so the third number should be 84. The printed 48 is not even a multiple of 42.
Concept
The second worked set is what makes this question solvable. (84, 63, 42) falls by 21 twice and looks like a plain arithmetic progression.
But (79, 47, 64) does not fall at all — its third number is larger than its second — so a progression rule is dead before you reach the options.
What survives both sets is a relation among the three numbers rather than a sequence: double the gap between the first two to get the third. When two worked sets disagree about the shape, the rule is a relation.
The bracketed NOTE bars digit operations, so do not look for a rule joining the 8 and the 4 of 84.
Key facts
- Set 1: 84 − 63 = 21 and 2 × 21 = 42.
- Set 2: 79 − 47 = 32 and 2 × 32 = 64.
- The three numbers need not decrease — in (79, 47, 64) the third exceeds the second.
Study next
Common traps
- Reading (84, 63, 42) as an arithmetic progression and never testing the second set
- Taking the third number as the gap itself rather than twice the gap
- Testing an option against one worked set only, where a near-rule can survive
Three-number set analogies with two worked sets recur across the 2024 shifts — also asked 10 Sep 2024, 09:00, Reasoning Q.9 (sets (79, 58, 62) and (54, 33, 37)) and 9 Sep 2024, 16:00, Reasoning Q.23 (sets (34, 47, 62) and (119, 142, 167)).
Related PYQs
No directly related past PYQ was found.