Study the below table and answer the question that follows. Day of the week → Distance jogged (in km) Monday — 6 Tuesday — 5.5 Wednesday — 5.5 Thursday — 7 Friday — 5 Saturday — 3.5 Sunday — 7.5 If 300 calories are burned by jogging 6 km, then how many calories were burnt in the given week?

Correct — B. The table gives seven distances. Add them first, then apply the calorie rate once.

Mon + Tue + Wed = 6 + 5.5 + 5.5 = 17 km
Add Thu 7 → 24 km
Add Fri 5 → 29 km

Add Sat 3.5 → 32.5 km
Add Sun 7.5 → 40 km for the week

Rate: 300 calories per 6 km, so 300 ⁄ 6 = 50 calories per km.
40 × 50 = 2,000 calories → option (b)

Why the others are wrong

• (a)
  1600 — 1600 is what 32 km would burn at 50 calories per km. The seven rows add to 40 km, eight kilometres more, so this is an under-count of the column rather than a wrong rate.
• (c)
  2200 — 2200 needs 44 km. The column gives 40 km, so this over-counts by exactly 4 — which is what happens if Saturday's 3.5 is read as a second 7.5.
• (d)
  1800 — 1800 is either 36 km at the correct rate, or 300 × 6 if you multiply the rate by Monday's distance instead of by the week's 40 km. Both routes skip the total.

This is the unitary method sitting on top of a data table, and the two halves are independent.

First the table: seven values, no weighting, plain addition to 40 km. Nothing in the question asks you to treat weekdays and weekend differently.

Then the rate: 300 calories buy 6 km, so one kilometre costs 50 calories. Find the unit rate once and apply it to the total — never day by day, which multiplies your chances of an arithmetic slip by seven.

Key facts

• The seven distances in the table add to 40 km.
• 300 calories per 6 km is a unit rate of 50 calories per kilometre.
• 40 km at 50 calories per km is 2,000 calories.
• The half-kilometre entries (5.5, 5.5, 3.5, 7.5) sum to 22, which is a quick way to check the addition.

Common traps

• Adding only the five weekdays and leaving Saturday and Sunday out
• Multiplying 300 by the number of days instead of by the distance
• Applying 300 calories to each day's run regardless of how long it was

No directly related past PYQ was found.