Amit and Bilal buy goods for ₹1,500 and ₹2,000, respectively. Amit marks his goods up by y%, while Bilal marks his goods up by 2y% and offers a discount of y%. If both make the same profit, then find the value of y.
- (a)10.5
- (b)12.5
- (c)11.5
- (d)12
Answer
Why
Correct — B. Amit only marks up, so his profit is 1500 × y⁄100 = 15y.
Bilal's marked price = 2000(1 + 2y⁄100) = 2000 + 40y
After the y% discount, SP = (2000 + 40y)(1 − y⁄100)
= 2000 + 40y − 20y − 0.4y² = 2000 + 20y − 0.4y²
Bilal's profit = SP − 2000 = 20y − 0.4y²
Equal profits: 15y = 20y − 0.4y²
0.4y² = 5y, so y = 5 ⁄ 0.4 = 12.5 → option (b).
Check: Amit makes 12.5% of 1500 = ₹187.50; Bilal sells at 2500 × 0.875 = ₹2,187.50, also ₹187.50 of profit.
Why the others are wrong
- (a)10.5 — At y = 10.5 Bilal earns ₹165.90 against Amit's ₹157.50. Bilal is still ahead, so the profits are not yet equal.
- (c)11.5 — y = 11.5 leaves Bilal on ₹177.10 and Amit on ₹172.50. The gap has narrowed but has not closed.
- (d)12 — y = 12 is the near miss: Bilal makes ₹182.40, Amit ₹180. Equality arrives only at 12.5.
Concept
A markup followed by a discount is not the two percentages netted off, because the discount is taken on the marked price, not on the cost. Write it multiplicatively:
SP = CP × (1 + m⁄100) × (1 − d⁄100).
Expanding leaves a −md⁄10000 cross term. That is why Bilal's '2y% up, y% off' is worth a net markup of only y − 2y²⁄100 percent, not y percent — and it is the term the whole question turns on.
Both cost prices matter and neither cancels.
Note that the question equates profit amounts, not percentages. Equating the percentages instead would give y = y − 2y²⁄100, whose only solution is y = 0.
Key facts
- Successive markup and discount multiply: SP = CP × (1 + m⁄100) × (1 − d⁄100).
- A markup of 2y% followed by a discount of y% leaves a net markup of (y − 2y²⁄100) percent.
- Profit is always measured against cost price, not marked price.
- At y = 12.5 both men make ₹187.50, but that is 12.5% for Amit and 9.375% for Bilal.
Study next
Common traps
- Treating '2y% up then y% off' as a net y% markup and losing the quadratic entirely.
- Cancelling y without noting that y = 0 is the discarded root of 0.4y² = 5y.
- Equating profit percentages when the question equates profit amounts.
SSC moves the unknown around inside the same markup-and-discount frame.
Cost given as 75% of marked price, gain wanted after a 15% discount, at Quant Q.19 of 11 Sep 2024, 12:30. Four rival discount schemes set against each other at Quant Q.18 of this paper (23 Sep 2024, 09:00), which asks which of them sells cheapest.
Related PYQs
No directly related past PYQ was found.