P, Q and R are the three angles of a triangle. If P − Q = 20° and Q − R = 26°, then ∠ P is equal to:
- (a)82°
- (b)46°
- (c)52°
- (d)92°
Answer
Why
Correct — A. Rule: the three angles of a triangle add to 180°.
Express both other angles through Q:
P = Q + 20°, R = Q − 26°
(Q + 20) + Q + (Q − 26) = 180
3Q − 6 = 180 → 3Q = 186 → Q = 62°
P = 62 + 20 = 82° → option (a)
Check: 82 + 62 + 36 = 180 ✔
Why the others are wrong
- (b)46° — 46° is 20 + 26, the total gap between P and R, not an angle of the triangle. Take P = 46° and the other two become 26° and 0°, which is not a triangle.
- (c)52° — 52° fails the sum test: P = 52° forces Q = 32° and R = 6°, adding to 90° rather than 180°. With the gaps fixed, any P below 82° leaves the triangle short.
- (d)92° — 92° overshoots. P = 92° gives Q = 72° and R = 46°, a total of 210°, so the largest angle has been pushed 10° too far.
Concept
Two differences and one total make three equations in three unknowns, but you never need three variables — write everything in terms of the middle angle Q.
P is 20° above Q and R is 26° below it, so the sum is 3Q − 6. Setting that equal to 180° is the entire question.
The angles come out as 82°, 62° and 36°: one triangle, no ambiguity, and the differences confirm themselves at 20° and 26°.
Key facts
- The interior angles of any triangle total 180°.
- P − Q = 20° and Q − R = 26° together give P − R = 46°.
- The solution here is P = 82°, Q = 62° and R = 36°.
Study next
Common traps
- Adding 26° instead of subtracting it when writing R in terms of Q.
- Answering with Q = 62° when the question asked for P.
- Treating 20° and 26° as angles rather than as differences.
SSC states the differences and asks for one named angle, so the marks are lost in bookkeeping rather than geometry. The same substitute-and-solve step settles Quant Q.3 and Q.7 in this shift.
Related PYQs
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