SSC CGL 2024 Tier-I · 19 September 2024, Shift 1 · Quantitative Aptitude · Question 12 of 100

Text as printed on a candidate's response sheet for this shift; answer per SSC's tentative key as marked on that sheet. Solution last reviewed 10 September 2026.

Where this paper and its answers come from

SSC does not publish CGL question papers or a public answer key. The questions and options here are reproduced as printed on a candidate's own response sheet for this shift — the Commission's text, unchanged. Each answer is SSC's tentative key as marked on that sheet; SSC allowed challenges to it and never publishes a final key. The solutions are written by UnlockIAS.

A student studying in 6th class scored the following marks in 6 subjects. The maximum marks for each subject are 100. What are the average marks scored by the student?

(a)94.5
(b)95
(c)96
(d)92.5

Answer

Why

Correct — A. Six subjects are listed, so add all six marks and divide by 6.

Hindi 98, English 97, Mathematics 93
98 + 97 + 93 = 288

Social Science 94, Computer 92, Science 93
94 + 92 + 93 = 279

Total = 288 + 279 = 567
Average = 567 ⁄ 6 = 94.5 → option (a)

Why the others are wrong

(b)
95 — 95 is 94.5 rounded up, and it is also what you get by dropping Computer's 92: 475 ⁄ 5 = 95. All six rows count, and 567 ⁄ 6 does not land on a whole number.
(c)
96 — 96 needs a total of 576, nine marks more than the table carries. Recheck the addition rather than the division — 567 is the figure the six rows give.
(d)
92.5 — 92.5 needs a total of 555, twelve marks below the table's 567. The six printed rows are 98, 97, 93, 94, 92 and 93, and no reading of them adds to 555.

Concept

The average of a plain list is the total divided by the number of entries — here six subjects, so six entries.

The 'maximum marks 100' line matters only if a percentage is wanted. For the average mark it changes nothing: 567 ⁄ 6 = 94.5 whether the papers are out of 100 or out of 50.

Add in two groups of three rather than one long chain. The intermediate totals 288 and 279 are quick to re-verify if the final figure looks wrong.

The marks arrive as a two-column image, Subjects against Marks, with six rows: Hindi 98, English 97, Mathematics 93, Social Science 94, Computer 92, Science 93. Read every row before adding.

Key facts

The six marks are 98, 97, 93, 94, 92 and 93, totalling 567.
Average marks = total marks ÷ number of subjects = 567 ÷ 6 = 94.5.
Because each paper is out of 100, the percentage here is numerically the same, 567 ÷ 600 × 100 = 94.5%.

Study next

Weighted average, for when subjects carry different maximum marksAggregate percentage against average mark, and when the two numbers coincideReading a two-column table without losing a row under time pressure

Common traps

Dividing by five after skipping a row in the image.
Rounding 94.5 up to 95 because a whole number is on offer.
Treating the average mark as the percentage when the maxima are not all 100.

The data arrives as a picture and the arithmetic is kept trivial, so the marks go to whoever reads all six rows correctly.

A harder table, four students across papers of 175 marks each, is set at Quant Q.23 of the same 19 Sep 2024, 09:00 sitting, where an aggregate percentage is wanted instead.

Related PYQs

No directly related past PYQ was found.