If x is an integer such that x + 1⁄x = 65⁄8, then find the value of x − 1⁄x.

- (a)

- (b)

- (c)

- (d)

Answer
Why
Correct — C. The stem is an image: if x is an integer with x + 1⁄x = 65⁄8, find x − 1⁄x.
Read 65⁄8 as a mixed number:
65⁄8 = 8 + 1⁄8, which is exactly the shape x + 1⁄x when x = 8.
Substitute:
x − 1⁄x = 8 − 1⁄8 = (64 − 1)⁄8 = 63⁄8 → option (c), the picture showing 63 over 8.
Why the others are wrong
- (a)63⁄6 has the right numerator over the wrong denominator. The quantity subtracted is 1⁄8, so the common denominator can only be 8.
- (b)36⁄8 is 4.5, far below 8 − 1⁄8. The subtraction removes only one-eighth, so the numerator falls from 64 to 63, not to 36.
- (d)32⁄6 changes numerator and denominator at once. Neither 32 nor 6 can come out of 8 − 1⁄8, whose value is just under 8.
Concept
Two routes reach the same place, and knowing both saves a minute.
Reading route: 65⁄8 is the mixed number 8 + 1⁄8, and x + 1⁄x has that same shape, so x = 8 can be read straight off. This works only because the stem promises x is an integer.
Identity route: (x − 1⁄x)² = (x + 1⁄x)² − 4, so the square is 4225⁄64 − 256⁄64 = 3969⁄64, and its root is 63⁄8.
The identity route produces ±63⁄8. Only the positive value is printed, and it is the one x = 8 gives — the other root of the equation, x = 1⁄8, is not an integer.
Key facts
- 65⁄8 read as a mixed number is 8 + 1⁄8, which fixes x = 8.
- (x + 1⁄x)² − (x − 1⁄x)² = 4 for every non-zero x.
- 8 − 1⁄8 = 63⁄8 = 7.875.
Study next
Common traps
- Solving 8x² − 65x + 8 = 0 by formula when the mixed number can be read in one glance
- Ignoring the integer condition, taking x = 1⁄8 and answering with the negative value
The options for this item are pictures, so the last step is matching a computed fraction to an image rather than to text. Value-finding by structure is also asked at 12 Sep 2024, 09:00, Quant Q.19, where 28.9 : x :: x : 36.1 has to be solved for x.
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