What will come in place of ‘?’ in the following equation, if ‘+’ and ‘–‘ are interchanged and ‘×’ and ‘÷’ are interchanged? 6 ÷ 8 – 91 × 13 + 30= ?
- (a)20
- (b)25
- (c)22
- (d)23
Answer
Why
Correct — B. Rewrite the line with the symbols swapped, then apply BODMAS to the new line.
Given: 6 ÷ 8 − 91 × 13 + 30
Swapped: 6 × 8 + 91 ÷ 13 − 30
6 × 8 = 48
91 ÷ 13 = 7 (13 × 7 = 91)
48 + 7 = 55
55 − 30 = 25 → option (b).
Why the others are wrong
- (a)20 — 20 needs 48 + 7 to come to 50. Those two terms make 55, and 55 − 30 = 25.
- (c)22 — 22 needs 91 ÷ 13 to be 4. The quotient is 7, because 13 × 7 = 91.
- (d)23 — 23 needs 6 × 8 to read 46. The product is 48.
Concept
Interchange questions are marked on care rather than on arithmetic. The numbers are kept small on purpose.
Rewrite the whole line with the swapped symbols before you calculate anything. Reading the swap while you compute is what produces the near-miss answers the options are built from.
Then run BODMAS on the rewritten line. The multiplication 6 × 8 and the division 91 ÷ 13 are both settled before the addition and the subtraction, whatever order they are printed in.
Both swaps matter. Exchanging only the multiplication and division signs leaves 6 × 8 − 91 ÷ 13 + 30 = 71, which is not offered — the sign that a step was skipped rather than an arithmetic slip made.
Key facts
- After the swap the line reads 6 × 8 + 91 ÷ 13 − 30.
- 91 ÷ 13 = 7, since 13 × 7 = 91.
- 48 + 7 − 30 = 25.
Study next
Common traps
- Swapping only one of the two pairs of symbols.
- Working left to right after the swap, which folds the subtraction into the division.
- Rounding 91 ÷ 13 instead of checking that 13 divides 91 exactly.
The identical stem, with the same two swaps on larger numbers, is set at Reasoning Q.17 of this shift. The method carries over unchanged: rewrite the line first, then apply BODMAS.
Related PYQs
No directly related past PYQ was found.