Simplify the following. 16 ÷ 2− 7 × 15 ÷ 3 + 5 × 5 + 4 × 3 − 10
- (a)1
- (b)-1
- (c)0
- (d)2
Answer
Why
Correct — C. There are no brackets, so clear every × and ÷ first, left to right, then the + and − left to right.
16 ÷ 2 = 8
7 × 15 ÷ 3 = 105 ÷ 3 = 35
5 × 5 = 25 and 4 × 3 = 12
The line is now 8 − 35 + 25 + 12 − 10.
8 − 35 = −27, then −27 + 25 = −2
−2 + 12 = 10, then 10 − 10 = 0 → option (c).
Why the others are wrong
- (a)1 — 1 needs the running total after 8 − 35 to be −26. That subtraction is −27, and the terms after it (+25, +12, −10) are not in dispute.
- (b)-1 — −1 needs that same running total to be −28, or 5 × 5 read as 24. Both products are exact: 8 − 35 = −27 and 5 × 5 = 25.
- (d)2 — 2 needs 8 − 35 taken as −25, which means subtracting 33 rather than 35. The value of 7 × 15 ÷ 3 is 35 whichever way you group it.
Concept
BODMAS fixes the order, and the two rules people drop are the ones that decide this line.
× and ÷ rank equally, and so do + and −. Inside a rank you work left to right — not multiplication before division, and not addition before subtraction.
So 7 × 15 ÷ 3 means (7 × 15) ÷ 3 = 35, and here 7 × (15 ÷ 3) happens to give 35 too, so the grouping does not bite.
In 8 − 35 + 25 it does bite: left to right it is (8 − 35) + 25 = −2, never 8 − (35 + 25) = −52.
Every option sits within 2 of the true value, so this question rewards one careful pass rather than a re-check of the rule.
Key facts
- Multiplication and division share one rank in BODMAS and are worked left to right.
- Addition and subtraction share the next rank and are also worked left to right.
- The four products here are 8, 35, 25 and 12, and 8 − 35 + 25 + 12 − 10 = 0.
- Attaching each minus sign to the number after it turns the line into 8 + (−35) + 25 + 12 + (−10), which may then be added in any order.
Study next
Common traps
- Grouping the line as 8 − (35 + 25), which reads −52 at that point and finishes at −50
- Reading 16 ÷ 2 − 7 as 16 ÷ (2 − 7)
- Losing a single unit in 8 − 35, which lands exactly on a printed option
SSC sets these either as a plain chain, as here, or wrapped in brackets and 'of' so the order has to be argued twice.
Also asked 09 Sep 2024, 12:30, Quant Q.24 (21 − 4.9 ÷ 7 + 3.9 × 0.4 + 0.9) and 10 Sep 2024, 16:00, Quant Q.6 (45 ÷ 3 + 4 × A − 48 ÷ 24 + 4 = 1, solve for A).
Related PYQs
No directly related past PYQ was found.