In a certain code language, ‘HUSBAND’ is written as ‘JVUDBPF’ and ‘SISTER’ is written as ‘UJUVFT’. How will ‘BROTHER’ be written in that language?
- (a)DJTFPTV
- (b)FJPVDTT
- (c)DTPVJFT
- (d)TFVJTPD
Answer
Why
Correct — C. Rule: vowels move +1 along the alphabet, consonants move +2.
Test it on SISTER: S+2 = U, I+1 = J, S+2 = U, T+2 = V, E+1 = F, R+2 = T, giving UJUVFT.
Test it on HUSBAND: H+2 = J, U+1 = V, S+2 = U, B+2 = D, A+1 = B, N+2 = P, D+2 = F, giving JVUDBPF.
Now encode BROTHER letter by letter:
B+2 = D, R+2 = T, O+1 = P, T+2 = V,
H+2 = J, E+1 = F, R+2 = T.
That spells DTPVJFT, option (c).
Why the others are wrong
- (a)DJTFPTV — DJTFPTV starts correctly with D but puts J second. The second letter of BROTHER is R, a consonant, so it must move two places to T; J is what H gives (H+2), and H is BROTHER's fifth letter.
- (b)FJPVDTT — FJPVDTT opens with F. B is a consonant and moves +2 to D, while F is what E gives — and E is the sixth letter of BROTHER, not the first.
- (d)TFVJTPD — TFVJTPD is built from the right seven letters in the wrong order — it is not even the reversal, which would read TFJVPTD. A substitution code replaces letters in place and never reorders them.
Concept
When a shift code will not fit one constant, split the letters into classes and test each class.
Here H to J, S to U, B to D, N to P and D to F are all +2, while U to V, A to B, I to J and E to F are all +1. The two classes are consonants and vowels.
Two coded words are given precisely so you can confirm the split rather than guess it. HUSBAND supplies the vowels U and A, and SISTER supplies I and E.
Then encode the target letter by letter and resist reordering. All four options here use the same seven letters, so the order is the whole question.
Y is never treated as a vowel in this item and never needs to be — BROTHER, HUSBAND and SISTER contain no Y. Do not assume a rule for a letter the paper has not shown you.
Key facts
- In this code every consonant advances 2 places and every vowel advances 1.
- HUSBAND becomes JVUDBPF and SISTER becomes UJUVFT under that rule.
- BROTHER encodes as D, T, P, V, J, F, T — that is DTPVJFT.
- All four options are rearrangements of the same seven letters, so their order alone decides the answer.
Study next
Common traps
- Fitting a single shift to the first word and never testing the second
- Choosing an option that carries the right letters in the wrong order
- Forgetting that BROTHER holds two Rs, both of which encode to T
SSC gives two worked words and asks for a third, which is exactly enough to pin a two-class rule. A number-based coding item appears in this shift at Reasoning Q.15.
Related PYQs
No directly related past PYQ was found.