If the ratio of the areas of two similar triangles is 25 : 144, the ratio of their corresponding sides is:
- (a)12 : 5
- (b)5 : 12
- (c)25 : 12
- (d)5 : 144
Answer
Why
Correct — B. Rule: in similar triangles the areas are in the ratio of the squares of corresponding sides.
So, writing the sides as s₁ and s₂:
(s₁ ⁄ s₂)² = 25 ⁄ 144
Take the square root of both sides:
s₁ ⁄ s₂ = √25 ⁄ √144 = 5 ⁄ 12
The corresponding sides are in 5 : 12 → option (b).
Why the others are wrong
- (a)12 : 5 — 12 : 5 is the right pair of numbers in the wrong order. The areas were given as 25 : 144, so the triangle of area 25 is named first, and its sides must be the shorter ones.
- (c)25 : 12 — 25 : 12 square-roots only the second term. Leaving 25 untouched compares an area against a length, which is not a ratio of anything. Both terms must be rooted.
- (d)5 : 144 — 5 : 144 square-roots only the first term. The missing step is √144 = 12; rooting one side of a ratio and not the other changes its value.
Concept
Similarity scales everything by the same factor k, but not to the same power.
Lengths — sides, perimeters, altitudes, medians, angle bisectors, radii of the inscribed and circumscribed circles — all scale by k.
Areas scale by k², because area is a length times a length. For similar solids, volumes scale by k³.
So an area ratio is always a square, and going from areas back to sides means taking a square root — of both terms.
25 : 144 is a deliberately friendly pair. Both are perfect squares, which is the signal that the question wants the root taken rather than a decimal worked out.
Key facts
- Ratio of areas of similar triangles = (ratio of corresponding sides)².
- The ratio of perimeters of similar triangles equals the ratio of their sides.
- √25 = 5 and √144 = 12, so 25 : 144 is exactly the square of 5 : 12.
- For similar solids the ratio of volumes is the cube of the ratio of edges.
Study next
Common traps
- Reversing the order of the ratio so the larger triangle comes first
- Square-rooting one term of the ratio and not the other
- Using the area ratio unchanged as the ratio of perimeters
SSC asks this step in both directions — sides to areas and areas to sides — and keeps the numbers as perfect squares so the whole question is one root. Congruence, the case k = 1, is asked in this same shift at Quant Q.14, and Quant Q.5 applies the same square law to a midpoint triangle.
Related PYQs
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