Simplify 21 − [6 + 7 − {3.22 − (1.1 × 0.2)}].
- (a)11
- (b)13
- (c)12
- (d)10
Answer
Why
Correct — A. Work outward from the innermost grouping, in BODMAS order.
Parentheses first:
1.1 × 0.2 = 0.22
Then the braces:
3.22 − 0.22 = 3
Then the square bracket:
6 + 7 = 13
13 − 3 = 10
Finally the subtraction standing outside it:
21 − 10 = 11 → option (a).
Why the others are wrong
- (b)13 — 13 would need the bracket to come to 8, since 21 − 8 = 13. The bracket is 6 + 7 − 3 = 10. Note that 13 is the value of 6 + 7 by itself, so the brace has simply never been subtracted.
- (c)12 — 12 would need the bracket to equal 9, which means a brace worth 4. The brace is 3.22 − 0.22, and that is exactly 3.
- (d)10 — 10 is the value of the square bracket itself — the answer to the second-last step. The expression still has 21 minus that bracket to go, which gives 11.
Concept
BODMAS with three levels of grouping. The rule is not left-to-right but innermost-first: parentheses ( ), then braces { }, then brackets [ ], and only then whatever stands outside.
Within a level, multiplication and division come before addition and subtraction — which is why 1.1 × 0.2 is resolved before the 3.22 is touched at all.
The decimals are cosmetic. 1.1 × 0.2 = 0.22 was chosen to cancel the 0.22 in 3.22 and leave a whole 3, so a brace that is not a whole number means a slipped decimal place.
The standard nesting order is ( ) inside { } inside [ ], and this stem follows it exactly.
A sign slip on the brace still lands close to the truth — 3.22 + 0.22 gives a bracket of 9.56 and a final 11.44 — so a candidate can feel right and still be wrong. Only the exact 3 produces a whole-number option.
Key facts
- Grouping is resolved innermost first: parentheses, then braces, then square brackets.
- 1.1 × 0.2 = 0.22, so the brace {3.22 − (1.1 × 0.2)} is exactly 3.
- The square bracket is 6 + 7 − 3 = 10, and 21 − 10 = 11.
Study next
Common traps
- Stopping at the bracket value of 10 and marking it.
- Multiplying 1.1 × 0.2 as 0.02 or as 2.2, either of which breaks the clean 3.
- Distributing the outer minus wrongly as 21 − 6 − 7 − 3, which gives 5.
The numbers are picked so the messy part cancels — spot the cancellation and the item is one line of arithmetic.
This shift runs the same trick again at Quant Q.6, where (0.58 × 0.58 × 0.58 − 0.001) ⁄ (0.58 × 0.58 + 0.058 + 0.01) hides the identity (a³ − b³) ⁄ (a² + ab + b²) = a − b with a = 0.58 and b = 0.1.
Related PYQs
No directly related past PYQ was found.