Four letter-clusters have been given, out of which three are alike in some manner and one is different. Select the one that is different. The odd one out is not based on the number of consonants/vowels or their position in the letter cluster

Correct — C.

Rule: each cluster steps +5 and then +5 again through the alphabet.

A(1) to F(6) to K(11): +5, +5
L(12) to Q(17) to V(22): +5, +5
D(4) to I(9) to N(14): +5, +5
P(16) to T(20) to X(24): +4, +4

PTX is the cluster built on gaps of four, so option (c) is the odd one out.

Why the others are wrong

• (a)
  AFK — A, F, K are five apart and then five apart again, the same as LQV and DIN, so AFK belongs to the group rather than standing outside it.
• (b)
  LQV — L, Q, V also step +5 and +5. It shares its structure with AFK and DIN, so it cannot be the different one.
• (d)
  DIN — D, I, N step +5 and +5 as well. The letters look scattered, but gaps are what the question compares, and these gaps match.

Odd-one-out on letter clusters is almost always decided by the gaps between the letters, not by the letters themselves.

Convert each letter to its alphabet position and take differences. Three clusters here give 5 and 5; one gives 4 and 4.

The stem rules out the other common basis in so many words: the odd one is not decided by the number of consonants or vowels or their position. That sentence is a hint rather than decoration — it says the answer lives in the arithmetic.

The EJOTY landmarks help: E is 5, J is 10, O is 15, T is 20, Y is 25, so any letter can be placed in a second.

Key facts

• A is 1, F is 6 and K is 11, so AFK has gaps of 5 and 5.
• P is 16, T is 20 and X is 24, so PTX has gaps of 4 and 4.
• The stem states the odd one out is not based on consonant or vowel counts, which removes the commonest wrong line of attack.

Common traps

• Comparing the clusters by look or by vowel count when the stem has explicitly ruled that out.
• Counting a gap inclusively and reading A to F as 6 instead of 5.

No directly related past PYQ was found.