The value of 15 ÷ 3 of 2 × 2 + 9 ÷ 18 of 2 × 4 − 4 ÷ 8 × 2 is:

- (a)5
- (b)

- (c)

- (d)8
Answer
Why
Correct — A. The stem is an image: the value of 15 ÷ 3 of 2 × 2 + 9 ÷ 18 of 2 × 4 − 4 ÷ 8 × 2.
Rule: 'of' is cleared before ÷ and × — it belongs with the bracket step, not with ordinary multiplication.
Block 1: 3 of 2 = 6, so 15 ÷ 6 × 2 = 2.5 × 2 = 5
Block 2: 18 of 2 = 36, so 9 ÷ 36 × 4 = 0.25 × 4 = 1
Block 3: no 'of' here, so left to right — 4 ÷ 8 × 2 = 0.5 × 2 = 1
Total = 5 + 1 − 1 = 5 → option (a).
Why the others are wrong
- (b)2¾ is below the opening block on its own. 15 ÷ 3 of 2 × 2 already comes to 5, and the last two blocks cancel each other, 1 − 1 = 0, so the total cannot drop under 5.
- (c)7¾ needs the middle block to be worth 3¾. With 'of' cleared first, 18 of 2 = 36 and 9 ÷ 36 × 4 = 1, which is what leaves the total at 5.
- (d)8 — 8 is what skipping 'of' in the middle block gives: 9 ÷ 18 × 2 × 4 = 4 in place of 9 ÷ 36 × 4 = 1. That one slip adds 3 and turns 5 into 8.
Concept
'Of' is not a synonym for ×. In the BODMAS order SSC applies, 'of' is resolved with the bracket step, ahead of division: 3 of 2 becomes 6 before the 15 is divided by anything.
Once every 'of' is cleared, ÷ and × rank equally and run left to right, then + and − run left to right in their turn.
The word only bites where a division sits in front of it. In 8 × 3 of 2 the reading makes no difference at all, but in 15 ÷ 3 of 2 it is the difference between 2.5 and 10.
Two of the four options are printed as images of mixed fractions, 2¾ and 7¾, so the plain text of the stem shows only the whole-number choices.
Both fractional options are baits for a half-finished division, and neither is reachable once the three blocks are evaluated as 5, 1 and 1.
Key facts
- In BODMAS as SSC applies it, 'of' is cleared with brackets, before division and multiplication.
- After 'of' is cleared, ÷ and × have equal rank and are applied left to right.
- 15 ÷ 3 of 2 is 15 ÷ 6 = 2.5, not 5 × 2 = 10.
- + and − also rank equally and run left to right, so a leading minus does not jump the queue.
Study next
Common traps
- Treating 'of' as plain multiplication and running everything left to right, which gives 23.
- Clearing 'of' in one block and forgetting it in the other, which lands on 8.
- Doing all multiplications before all divisions, so 4 ÷ 8 × 2 becomes 4 ÷ 16 = 0.25.
The plain BODMAS drill without any 'of' is set at 9 Sep 2024, 12:30, Quant Q.24, where 21 − 4.9 ÷ 7 + 3.9 × 0.4 + 0.9 comes to 22.76 on left-to-right rules alone.
The 'of' is what this stem adds on top, and it is where the marks go.
Related PYQs
No directly related past PYQ was found.