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UPSC 2007: Three dice (each having six faces with each face showing one number from 1 to 6) are rolled. What is the number of possible outcomes such that at least one die shows the number 2?
(a)36
(b)81
(c)91
(d)116
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Not attemptedCorrect Answer: (c) 91
Total outcomes for three fair dice = 6^3 = 216. Outcomes with no 2 showing = 5^3 = 125 (choices 1,3,4,5,6 on each die). Therefore outcomes with at least one 2 = 216 – 125 = 91, giving option (c).
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Frequently Asked Questions
What is the correct answer to this UPSC 2007 Science & Technology question?▼
The correct answer is option (c): 91. Watch the detailed video explanation in our Sherlocking Prelims course on UnlockIAS.
Which year was this Quantitative Aptitude question asked in UPSC Prelims?▼
This question was asked in UPSC CSE Prelims 2007, GS Paper 1, as Question 139. It falls under Science & Technology > Quantitative Aptitude.
What is the difficulty level of this UPSC question?▼
This question is rated "easy". It tests basic recall and most well-prepared aspirants should answer it correctly.
How many UPSC Prelims questions have been asked from Quantitative Aptitude?▼
UPSC has asked 178 questions from Quantitative Aptitude (under Science & Technology) across multiple years. Visit the topic page to see the full list and year-wise trends.