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UPSC 2006: 3 digits are chosen at random from 1, 2, 3, 4, 5, 6, 7, 8 and 9 without repeating any digit. What is the probability that their product is odd?
(a)2/3
(b)5/108
(c)5/42
(d)7/48
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Not attemptedCorrect Answer: (c) 5/42
The product of three digits will be odd only when all three digits selected are odd. There are 5 odd digits (1, 3, 5, 7, 9). Total ways = C(9,3)=84; favourable ways = C(5,3)=10. Probability = 10/84 = 5/42, i.e. option (c). ([mrunal.org](https://mrunal.org/2014/06/studyplan-csat-aptitude-paper-2-decision-making-maths-medium-low-priority-topics-sample-questions-free-studymaterial-part-3-3.html?utm_source=openai))
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Frequently Asked Questions
What is the correct answer to this UPSC 2006 Science & Technology question?▼
The correct answer is option (c): 5/42. Watch the detailed video explanation in our Sherlocking Prelims course on UnlockIAS.
Which year was this Quantitative Aptitude question asked in UPSC Prelims?▼
This question was asked in UPSC CSE Prelims 2006, GS Paper 1, as Question 68. It falls under Science & Technology > Quantitative Aptitude.
What is the difficulty level of this UPSC question?▼
This question is rated "easy". It tests basic recall and most well-prepared aspirants should answer it correctly.
How many UPSC Prelims questions have been asked from Quantitative Aptitude?▼
UPSC has asked 178 questions from Quantitative Aptitude (under Science & Technology) across multiple years. Visit the topic page to see the full list and year-wise trends.