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UPSC 2001: A worker reaches his factory 3 minutes late if his speed from his house to the factory is 5 km/hr. If he walks at a speed of 6 km/hr, then he reaches the factory 7 minutes early. The distance of the factory from his house is
(a)4 km
(b)5 km
(c)6 km
(d)7 km
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Not attemptedCorrect Answer: (b) 5 km
Let distance be D km. Time at 5 km h⁻¹ is D/5 h and at 6 km h⁻¹ is D/6 h; the difference equals 10 min = 1⁄6 h. Thus D/30 = 1⁄6 → D = 5 km. Only option (b) matches. ([licchavilyceum.com](https://licchavilyceum.com/upsc-civil-services-prelims-2001-solved-question-paper/?utm_source=openai))
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Frequently Asked Questions
What is the correct answer to this UPSC 2001 Science & Technology question?▼
The correct answer is option (b): 5 km. Watch the detailed video explanation in our Sherlocking Prelims course on UnlockIAS.
Which year was this Quantitative Aptitude question asked in UPSC Prelims?▼
This question was asked in UPSC CSE Prelims 2001, GS Paper 1, as Question 140. It falls under Science & Technology > Quantitative Aptitude.
What is the difficulty level of this UPSC question?▼
This question is rated "easy". It tests basic recall and most well-prepared aspirants should answer it correctly.
How many UPSC Prelims questions have been asked from Quantitative Aptitude?▼
UPSC has asked 178 questions from Quantitative Aptitude (under Science & Technology) across multiple years. Visit the topic page to see the full list and year-wise trends.