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UPSC 1999: At a given time, two players are standing on a play-field. The cartesian coordinates of their locations are (20, 60) and (-40, -20) units. What is the distance between the players?
(a)60 units
(b)80 units
(c)100 units
(d)140 units
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Not attemptedCorrect Answer: (c) 100 units
The separation is √[(20 – (–40))² + (60 – (–20))²] = √[(60)² + (80)²] = √(10 000) = 100 units. ([scribd.com](https://www.scribd.com/document/465263088/1999-upsc-prelims))
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Frequently Asked Questions
What is the correct answer to this UPSC 1999 Science & Technology question?▼
The correct answer is option (c): 100 units. Watch the detailed video explanation in our Sherlocking Prelims course on UnlockIAS.
Which year was this Quantitative Aptitude question asked in UPSC Prelims?▼
This question was asked in UPSC CSE Prelims 1999, GS Paper 1, as Question 148. It falls under Science & Technology > Quantitative Aptitude.
What is the difficulty level of this UPSC question?▼
This question is rated "easy". It tests basic recall and most well-prepared aspirants should answer it correctly.
How many UPSC Prelims questions have been asked from Quantitative Aptitude?▼
UPSC has asked 178 questions from Quantitative Aptitude (under Science & Technology) across multiple years. Visit the topic page to see the full list and year-wise trends.