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UPSC 1999: The average speed of a train in the onward journey is 25% more than that of the return journey. The train halts for one hour on reaching the destination. The total time taken for the complete to-and-fro journey is 17 hours covering a distance of 800 km. The speed of the train in the onward journey is
(a)45 km per hour
(b)47.06 km per hour
(c)50.00 km per hour
(d)56.25 km per hour
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Not attemptedCorrect Answer: (d) 56.25 km per hour
Let the onward speed be v km/h and the return speed be v/1.25 = 0.8 v km/h (since it is 25 % less). Time taken = 400/v + 400/(0.8 v) + 1 h = 900/v + 1 = 17 h ⇒ 900/v = 16 ⇒ v = 56.25 km h⁻¹. Hence option (d) is correct. The official 1999 key also gives option (d). ([scribd.com](https://www.scribd.com/document/465263088/1999-upsc-prelims?utm_source=openai))
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Frequently Asked Questions
What is the correct answer to this UPSC 1999 Science & Technology question?▼
The correct answer is option (d): 56.25 km per hour. Watch the detailed video explanation in our Sherlocking Prelims course on UnlockIAS.
Which year was this Quantitative Aptitude question asked in UPSC Prelims?▼
This question was asked in UPSC CSE Prelims 1999, GS Paper 1, as Question 134. It falls under Science & Technology > Quantitative Aptitude.
What is the difficulty level of this UPSC question?▼
This question is rated "moderate". It requires sound conceptual understanding of the topic.
How many UPSC Prelims questions have been asked from Quantitative Aptitude?▼
UPSC has asked 178 questions from Quantitative Aptitude (under Science & Technology) across multiple years. Visit the topic page to see the full list and year-wise trends.