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UPSC 1996: Two packs of cards are thoroughly mixed and shuffled and two cards are drawn at random, one after the other. What is the probability that both of them are Jacks?
(a)1/13
(b)2/13
(c)7/1339
(d)1/169
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Not attemptedCorrect Answer: (c) 7/1339
There are 8 Jacks in 2 packs (4 × 2). P(first Jack) = 8/104; after removing one Jack, P(second Jack) = 7/103. Combined probability = (8 × 7)/(104 × 103) = 56/10 712 = 7/1339, i.e. option (c). Other options mis-compute either the initial Jack count or forget to adjust the denominator after the first draw. ([licchavilyceum.com](https://licchavilyceum.com/upsc-civil-services-prelims-1996-solved-question-paper/?utm_source=openai))
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Frequently Asked Questions
What is the correct answer to this UPSC 1996 Science & Technology question?▼
The correct answer is option (c): 7/1339. Watch the detailed video explanation in our Sherlocking Prelims course on UnlockIAS.
Which year was this Quantitative Aptitude question asked in UPSC Prelims?▼
This question was asked in UPSC CSE Prelims 1996, GS Paper 1, as Question 149. It falls under Science & Technology > Quantitative Aptitude.
What is the difficulty level of this UPSC question?▼
This question is rated "moderate". It requires sound conceptual understanding of the topic.
How many UPSC Prelims questions have been asked from Quantitative Aptitude?▼
UPSC has asked 178 questions from Quantitative Aptitude (under Science & Technology) across multiple years. Visit the topic page to see the full list and year-wise trends.