Question
If x and y are two digits and the number 4x5y790 is divisible by 11, then what is the remainder, if x + y is divided by 11?
- (a)1
- (b)3
- (c)5
- (d)7
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Alternating digit sum = 4 − x + 5 − y + 7 − 9 + 0 = 7 − (x + y), which must be a multiple of 11, so x + y = 7 (or 18). In either case (x + y) mod 11 = 7.
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