A laser light beamed at the Moon takes 2.56 s to return to earth after reflection at the Moon's surface. How much is the radius of the lunar orbit around the Earth ?
- (1)7.68 × 10⁸ m
- (2)76.8 × 10⁵ km
- (3)38.4 × 10⁵ km
- (4)3.84 × 10⁸ m
Correct — option (4), 3.84 × 10⁸ m. The measurement described is laser ranging: a pulse is fired at the Moon, bounced off a reflector on its surface and detected again on Earth, and the time recorded is for the whole journey out and back. So the first step is to halve it. The round trip takes 2.56 seconds, therefore the one-way flight takes 1.28 seconds. The second step is to multiply by the speed of light, which is 3 × 10⁸ metres per second: distance = 3 × 10⁸ × 1.28 = 3.84 × 10⁸ metres. That is the Earth-Moon distance, which the stem calls the radius of the lunar orbit around the Earth, and it agrees with the accepted mean value of about 3.84 × 10⁵ kilometres — the same number, since one kilometre is 10³ metres. The option set demands one more piece of care than the arithmetic does, because it mixes units: the first and fourth rows are in metres and the second and third in kilometres, so nothing can be compared until everything is converted to a single unit. Convert the correct answer and it becomes 3.84 × 10⁵ km. Neither of the two kilometre rows carries that value: one reads 38.4 × 10⁵ km, which is 3.84 × 10⁶ km, and the other reads 76.8 × 10⁵ km, which is 7.68 × 10⁶ km. Each is ten times the metre-based value it otherwise resembles, so both are eliminated by conversion alone, and the whole of the work in this question lies in doing that conversion rather than in trusting the digits. The physical scale is worth carrying away as a check of its own. Light takes about 1.28 seconds to reach us from the Moon and about eight minutes and twenty seconds from the Sun, so any answer implying a Moon that light takes far longer to reach is describing something other than the Moon. Halving the round trip, multiplying by the speed of light and converting the units gives 3.84 × 10⁸ metres, which is option (4).
- (1)7.68 × 10⁸ m — This is the distance light travels in the whole 2.56 seconds — 3 × 10⁸ × 2.56 = 7.68 × 10⁸ metres — which is the round trip out to the Moon and back, not the distance to the Moon. It is the single commonest error in every echo-based measurement, whether the signal is laser light, radar or sonar, and it is worth building a permanent habit against: whenever a stem says a signal RETURNS, or is REFLECTED, or is an ECHO, halve the time before doing anything else. Write the halving down as the first line of the working rather than holding it in the head, because it is the step most easily lost when the arithmetic that follows is easy. The option is also the one a candidate is most likely to reach after a correct calculation performed too quickly, since every other element of the working is right and only the factor of two is missing — which is exactly why it is printed.
- (2)76.8 × 10⁵ km — This row makes two demands at once and fails both. Written out, 76.8 × 10⁵ km is 7.68 × 10⁶ kilometres. The round-trip distance in kilometres is 7.68 × 10⁵ km, so this value is not only the un-halved round trip rather than the distance to the Moon, it is also ten times that un-halved figure. Both faults have to be caught, and the way to catch them is to refuse to compare a row until it has been converted into the unit you have been working in. Bring it to metres and it becomes 7.68 × 10⁹ m, against a correct answer of 3.84 × 10⁸ m — different by a factor of twenty, which no reading of the stem can produce. The scale check settles it too: a Moon at seven and a half million kilometres would be some twenty times farther than the Moon actually is, and light would take about twenty-five seconds to reach it rather than the 1.28 seconds the stem itself implies.
- (3)38.4 × 10⁵ km — This is the most dangerous row in the set, because its digits are the right digits. Written out, 38.4 × 10⁵ km is 3.84 × 10⁶ kilometres, and the correct distance in kilometres is 3.84 × 10⁵ km — the same significant figures with the power of ten one step too high, which is to say ten times too far. A candidate who has done the halving and the multiplication correctly, arrived at 3.84 × 10⁸ metres, and then scanned the options for the familiar 3.84 will find it here and stop. The defence is mechanical: convert the row into your own working unit before accepting it, never the other way round. In metres this option reads 3.84 × 10⁹ m against a correct 3.84 × 10⁸ m, and the mismatch is then impossible to miss. When an option set mixes metres and kilometres, as this one does, it is testing conversion at least as much as it is testing the physics, and the correct digits appearing in the wrong row are the mechanism by which it does so.
Distances that cannot be walked out with a tape are measured by timing a signal of known speed, and the method is the same whether the signal is sound, radio or light. A pulse is sent, it reflects from the target, and the round-trip time is halved and multiplied by the speed of propagation. Sonar does this with sound in water to find the depth of the sea bed; radar does it with radio waves to find aircraft and to map the surfaces of Venus and the inner planets; laser ranging does it with light, and the Earth-Moon distance has been measured this way since retroreflector arrays were placed on the lunar surface — by the Apollo astronauts and by the Soviet Lunokhod rovers, which carried French-built reflectors. A retroreflector returns light back along the direction it came from, which is what makes the returning pulse detectable at all across such a distance. The speed of light in vacuum, about 3 × 10⁸ metres per second, is the constant that turns those times into distances, and it also supplies astronomy's larger units: light travels about 1.28 seconds from the Moon, about 8 minutes 20 seconds from the Sun, and one light year is the distance it covers in a year, roughly 9.46 × 10¹⁵ metres. The astronomical unit, the mean Earth-Sun distance, is about 1.496 × 10¹¹ metres. Lunar laser ranging is precise enough to have shown that the Moon is receding from the Earth by a few centimetres a year, a consequence of the tidal interaction between the two bodies.
This is a standard school-textbook problem on units and measurement, reproduced with its numbers intact, and MPSC uses items of this kind because they test three separate things in one line of working: whether a candidate halves the round-trip time, whether they hold the speed of light, and whether they can convert between metres and kilometres in scientific notation. The third is the part this particular option set is designed around. Two rows are printed in metres and two in kilometres — a mixture the stem gives no warning of — and the same significant digits recur across rows in different unit systems, 3.84 against 38.4 and 7.68 against 76.8. A candidate who computes correctly and then matches on digits alone can still lose the question. The rule that protects against it is simple and worth making automatic: finish the calculation in one unit, then convert each option into that unit before comparing, rather than converting your answer into the units of a row that looks promising. The same rule applies to every question in these papers where the options carry mixed units, and it costs perhaps fifteen seconds. Note also that the exponents are printed as typeset superscripts throughout, and are reproduced here as printed.
- In an echo or reflection measurement the recorded time is for the round trip, so it must be halved before being multiplied by the speed of the signal: 2.56 s round trip gives 1.28 s one way.
- With the speed of light taken as 3 × 10⁸ m s⁻¹, the Earth-Moon distance is 3 × 10⁸ × 1.28 = 3.84 × 10⁸ metres, which is 3.84 × 10⁵ kilometres and agrees with the accepted mean value.
- The option set mixes units — two rows in metres and two in kilometres — so every row must be converted into a single unit before it is compared with a calculated answer.
- Expressed in kilometres, the correct value is 3.84 × 10⁵ km; the two kilometre rows offered read 38.4 × 10⁵ km and 76.8 × 10⁵ km, which are 3.84 × 10⁶ km and 7.68 × 10⁶ km respectively.
- Light takes about 1.28 seconds to travel from the Moon to the Earth and about 8 minutes 20 seconds from the Sun; one light year is about 9.46 × 10¹⁵ metres and one astronomical unit about 1.496 × 10¹¹ metres.
- Lunar laser ranging is possible because retroreflector arrays were left on the Moon by the Apollo missions and by the Soviet Lunokhod rovers; the technique is precise enough to show that the Moon is receding from the Earth by a few centimetres a year.
A standard school-textbook problem on units and measurement, and it tests three separate things in one line of working: whether the round-trip time is halved, whether the speed of light is held, and whether metres and kilometres can be converted in scientific notation. The third is what this option set is designed around, and it is why a correct calculation can still lose the mark — finish in metres, match on digits alone, and a kilometre row wearing the expected digits is waiting. The rule that protects against it is to finish the calculation in one unit and then convert each printed row into that unit before comparing, rather than converting your own answer into the units of a row that looks promising; it costs perhaps fifteen seconds and applies to every question in these papers whose choices carry mixed units. The measurement itself is real: lunar laser ranging works because retroreflector arrays were left on the Moon by the Apollo astronauts and by the Soviet Lunokhod rovers, and it is precise enough to have shown that the Moon is receding from the Earth by a few centimetres a year.
- Forgetting to halve the round-trip time whenever a signal is described as returning, reflecting or echoing — the single commonest error in this family of problems
- Matching an option on its digits when the option is printed in a different unit from the one you calculated in
- Mishandling a power of ten during conversion, so that a correct value in metres becomes a value ten or a thousand times too large in kilometres
- Failing to notice that an option set mixes units at all, which this question's four rows do without any warning in the stem
- Skipping the plausibility check — light takes about 1.28 seconds to reach us from the Moon, so any answer implying a far longer flight time is not describing the Moon
Measurement questions in MPSC papers take three shapes. The first is a numerical of exactly this type: a round-trip time and a signal speed are given and a distance is asked for, with the trap in the halving, in the units, or in both. The second is a definitional item on the units themselves — what a light year measures, whether it is a unit of time or distance, what an astronomical unit is, how a parsec relates to them — and the light year being a distance rather than a duration is asked in almost every cycle somewhere. The third is a method question, asking which technique is used to measure a stated distance, from a parallax measurement of a nearby star to sonar for the depth of the sea. A single page holding the speed of light, the standard astronomical distances and the echo formula answers all three, and the discipline of converting every option into one unit before comparing protects the marks.
No directly related past PYQ was found.
- practice — not a real PYQ
A sonar pulse sent vertically downward from a ship returns from the sea bed after 4 seconds. If the speed of sound in sea water is 1500 m s⁻¹, what is the depth of the sea at that point ?
- (a)6000 m
- (b)3000 m
- (c)1500 m
- (d)375 m
Answer(b) 3000 m — the four seconds covers the journey down and back, so the one-way time is 2 seconds and the depth is 1500 × 2 = 3000 metres. The figure of 6000 metres in the first option is the total path travelled by the pulse and is what a candidate obtains by omitting the halving, which is the same error that the un-halved option in a lunar laser-ranging problem is built to catch. The method is identical in both cases; only the signal and its speed change.
- practice — not a real PYQ
A light year is a unit of which of the following ?
- (a)Time
- (b)Distance
- (c)Speed
- (d)Luminosity
Answer(b) Distance — a light year is the distance light travels in one year in vacuum, about 9.46 × 10¹⁵ metres, and the word 'year' in its name refers to the time taken rather than to the quantity measured. The same construction gives the light second, which is the distance light covers in one second and is roughly the scale of the Earth-Moon separation, since light takes about 1.28 seconds to cross it. The astronomical unit, the mean Earth-Sun distance of about 1.496 × 10¹¹ metres, is the other standard distance unit in this family.