Q: Fourier series representation of f(x) = x + 1 for −1 ≤ x ≤ 1 is
(a)f(x) = 1 − (2/π) ∑ [(−1)ⁿ⁺¹/n] sin(nπx)
(b)f(x) = −1 − (2/π) ∑ [(−1)ⁿ⁺¹/n] sin(nπx)
(c)f(x) = 1 + (2/π) ∑ [(−1)ⁿ⁺¹/n] sin(nπx)
(d)f(x) = −1 + (2/π) ∑ [(−1)ⁿ⁺¹/n] sin(nπx)
Correct Answer: (c)
Detailed explanation coming soon.