Q: Let f(x) = {1, |x| < a; 0, |x| > a} and g(x) = {1, 0 < x < a; 0, otherwise}, then the Fourier transform of 3f(x) − 2g(x) is
(a)√(2/π) {3sinωa/ω + (1 − e^{iωa})/(iω)}
(b)√(2/π) {3sinωa/ω − (1 + e^{−iωa})/(iω)}
(c)√(2/π) {−3sinωa/ω − (1 − e^{−iωa})/(iω)}
(d)√(2/π) {3sinωa/ω − (1 − e^{−iωa})/(iω)}
Correct Answer: (d)
Detailed explanation coming soon.