ESE 2022Q87
Q: From the Taylor series for y(x), what is the value of y(0·1) correct to four decimal places if y(x) satisfies y′ = x − y² and y(0) = 1 ?
(a)0·9138
(b)0·7254
(c)0·5286
(d)0·3524
Correct Answer: (c)
Detailed explanation coming soon.
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