ESE 2020Q23
Q: The solution of the differential equation (1 + y²) dx = (tan⁻¹y − x) dy is
(a)x = tan⁻¹y + 1 + ce^{−tan⁻¹y}
(b)x = tan⁻¹y − 1 + ce^{−tan⁻¹y}
(c)x = ½ tan⁻¹y − 1 + ce^{−tan⁻¹y}
(d)x = ½ tan⁻¹y + 1 + ce^{−tan⁻¹y}
Correct Answer: (b)
Detailed explanation coming soon.